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Butoxors [25]
4 years ago
12

Explanation capabilities can be added to a decision support system (DSS) by integrating it with a(n) _____. a. natural-language

processing system b. database management library c. artificial neural network d. expert system
Computers and Technology
2 answers:
Sladkaya [172]4 years ago
4 0

Answer:

Option D

Explanation:

An expert system is a program incorporated into a computer system which uses artificial intelligence technology in simulations of behaviour or outcomes/ solutions to a problem that is evident of expert knowledge and experience in that particular field of research.

deff fn [24]4 years ago
3 0

Answer:

d. expert system

Explanation:

Among the types of systems that support the decision-making process, the following are identical:

Decision Support Systems (DSS: Decision Support Systems)

Support decision making by generating and systematically evaluating different alternatives or decision scenarios.

A DSS does not solve problems, since it only supports the decision-making process. The responsibility of making a decision, of adopting and making it is the responsibility of the administrators, not of the DSS. It can be used to obtain information that reveals the key elements of the problems and the relationships between them. It can also be used to identify, create and communicate available courses of action and decision alternatives.

Support Systems for Group Decision Making (Group Decision Support Systems). They cover the objective of achieving the participation of a group of people during decision-making in anonymous and consensus environments, supporting simultaneous decisions.

Expert Support Systems for Decision Making (DEss: Expert Decision Supprt Systems). They allow to load knowledge bases that are integrated by a series of common sense rules so that different users consult them, support decision making, training.

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3 years ago
Write a program that contains three methods:
Reil [10]

Answer:

#include <stdio.h>//defining header file

int max (int x, int y, int z) //defining a method max that hold three parameters

{

   if(x>=y && x>=z)//defining if block that checks x is greater then y and x is greater then z

   {

       return x;//return the value x

   }

   else if(y>z)//defining else if block it check y is greater then z

   {

       return y;//return the value y

   }

   else//else block

   {

       return z;//return the value z

   }

}

int min (int x, int y, int z) //defining a method max that holds three parameters

{

if(x<=y && x<=z) //defining if block that check x value is less then equal to y and less then equal to z

{

return x;//return the value of x

}

if(y<=x && y<=z) //defining if block that check y value is less then equal to x and less then equal to z

{

return y;//return the value of y

}

if(z<=x && z<=x)//defining if block that check z value is less then equal to x  

{

return z;//return the value of z

}

return x;//return the value of z  

}

int average (int x, int y, int z) //defining average method that take three parameters

{

int avg= (x+y+z)/3;//defining integer variable avg that calculate the average

return avg;//return avg value

}

int main()//defining main method

{

   int x,y,z;//defining integer variable

   printf("Enter first value: ");//print message

   scanf("%d",&x);//input value from the user end

   printf("Enter Second value: ");//print message

   scanf("%d",&y);//input value from the user end

   printf("Enter third value: ");//print message

   scanf("%d",&z);//input value from the user end

   printf("The maximum value is: %d\n", max(x,y,z));//calling the method max

   printf("The minimum value is: %d\n", min(x,y,z));//calling the method min

   printf("The average value is: %d\n", average(x,y,z));//calling the method average

   return 0;

}

Output:

Enter first value: 45

Enter Second value: 35

Enter third value: 10

The maximum value is: 45

The minimum value is: 10

The average value is: 30

Explanation:

In the above-given code, three methods "max, min, and average" is declared that holds three integer variable "x,y, and z" as a parameter and all the method work as their respective name.

  • In the max method, it uses a conditional statement to find the highest number among them.
  • In the min method, it also uses the conditional statement to find the minimum value from them.
  • In the average method, it defined an integer variable "avg" that holds the average value of the given parameter variable.
  • In the main method, three variable is defined that inputs the value from the user end and passes to the method and print its value.      
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Describe how to add slide numbers and image to a Microsoft power point presentations ?​
Dafna11 [192]
Oh we did this in class I know this
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3 years ago
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ipn [44]

Answer:

C++ code explained below

Explanation:

#include<bits/stdc++.h>

#include <iostream>

using namespace std;

int FiboNR(int n)

{

int max=n+1;

int F[max];

F[0]=0;F[1]=1;

for(int i=2;i<=n;i++)

{

F[i]=F[i-1]+F[i-2];

}

return (F[n]);

}

int FiboR(int n)

{

if(n==0||n==1)

return n;

else

return (FiboR(n-1)+FiboR(n-2));

}

int main()

{

long long int i,f;

double t1,t2;

int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};

cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;

cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;

for(i=0;i<16;i++)

{

clock_t begin = clock();

f=FiboR(n[i]);

clock_t end = clock();

t1=double(end-begin); // elapsed time in milli secons

begin = clock();

f=FiboNR(n[i]);

end = clock();

t2=double(end-begin);

cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds

}

return 0;

}

7 0
3 years ago
Maya wrote a program and forgot to put the steps in the correct order. Which step does Maya need to review? Pattern following Pl
Drupady [299]

Answer:

Sequencing

Explanation:

7 0
3 years ago
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