Answer:
<h2>210 gaL 60 % Antifreeze II</h2>
Step-by-step explanation:
In the problem, there are two types of antifreeze
antifreeze I and
antifreeze II
antifreeeze I 20 ----70 gal
Antifreeze II 60 ----- x gal
Total 50 ---------------- (70 + x ) gal
20*70+60*x=50(70+x)
1400+60x=3500+50x
60x-50x=3500-1400
10x=2100
x= 210
x=210 gaL 60 % Antifreeze II
Answer:
y=-3x-3
Step-by-step explanation:
To get a perpendicular line you take the negative reciprocal of the slope, so in this case it would equal -3. Now use point-slope form to get your equation. Point slope form says that y-y1=m(x-x1) where m is your slope and x1 and y1 are the points that the graph passes through. So in this case x1=-3, y1=6, and m=-3. This gives you the equation y-6=-3(x+3). Distribute to y-6=-3x-9, and finally add 6 to both sides to get y=-3x-3
Answer:
Step-by-step explanation:
.6(2k-3)=3(4k+5) foil
1.2K-1.8=12k+15 subtract 1.5k from both sides
-1.8=10.8k+15 subtract 15 from both sides
-16.8=10.8k divide by 10.8
k= -1.5
Answer:
(B) 26°
Step-by-step explanation:
The angle at A made by the radius and the tangent is 90°. The angle at O is the same as arc AB, 64°. The acute angles in a right triangle are complementary, so the angle at C is the complement of 64°.
∠ACB = 90° -64°
∠ACB = 26°
