a. The ball's horizontal and vertical positions at time
are given by


The ball reaches the net when
:

At this time, the ball is at an altitude of

which is 1.40 m - 0.900 m = 0.500 m above the net.
b. The change in angle gives the ball the new position functions


The ball reaches the net at time
such that

at which point the ball's vertical position would be

so that the ball does not clear the net with 0.343 m - 0.900 m = -0.557 m.
Like-charged bodies will repel each other. When they're brought
closer together, they'll repel each other with even more force.
The gravitational force of two objects, by definition, is given by:

Where,
G: gravitational constant
m1: mass of object number 1.
m2: mass of object number 2.
d: distance between both objects.
Therefore, according to the given equation, a change that always results in an increase in gravitational force is:
Increase in the mass of the objects and decrease in the distance between them.
Answer:
A change that will always result in an increase in the gravitational force between two objects is:
Increase in the mass of the objects and decrease in the distance between them.
Given:
Dy= 20 m
Vi = 5.0 m/s horizontally
A=9.81 m/s^2
Find:
Horizontal displacement
Solution:
D=ViT+(1/2)AT^2
Dy=(1/2)AT^2
T^2=Dy/(1/2)A
T=sqrt(Dy/(1/2)A)
T=sqrt(20/4.905)
T=2.0s
Dx=ViT
Dx=(5.0)(2.0)
Dx=10. meters