Hannah made a chart to describe speed and velocity.

Physics

1 answer:

morpeh [17]4 years ago

9 0

Answer:

Describe the calculation for speed as "dividing distance by time."

Explanation:

As we know that distance is the ratio of distance and time

so we can say that the speed of the given object is

$speed = \frac{distance}{time}$

while velocity is a vector term

so it is defined as the ratio of displacement and time

$velocity = \frac{displacement}{time}$

so speed must have magnitude while velocity must have direction and magnitude both

so correct answer will be

Describe the calculation for speed as "dividing distance by time."

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A industrial (large) pressure cooker operates at 275 kPa. Initially there is 10 kg of water at 20Â°C, the cooker is operated unt

alex41 [277]

Answer:

$Q_{in} = 25349.92\,kJ$

Explanation:

Let establish a control volume in the industrial pressure cooker, which is a transient state system. From the First Law of Thermodynamics, the heating process is modelled:

$Q_{in} + m_{1}\cdot h_{1} - m_{2}\cdot h_{2} = (m_{1}-m_{2})\cdot u_{2} - m_{1}\cdot u_{1}$

The heat transfered to the cooker is:

$Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}$

Properties at each state are described below:

State 1

$u_{1} = 83.913\,\frac{kJ}{kg}$

$h_{1} = 83.915\,\frac{kJ}{kg}$

State 2

$u_{2} = 2540.1\,\frac{kJ}{kg}$

$h_{2} = 2720.9\,\frac{kJ}{kg}$

The heat transfered to the cooker is:

$Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )$