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vovikov84 [41]
4 years ago
14

Which letters in the image represent the heart's ventricles?

Physics
2 answers:
faltersainse [42]4 years ago
6 0

Here you go this the image for this question your asking for . :)

Lena [83]4 years ago
4 0
What picture...? You didn't upload one
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An object, whose mass is 0.660 kg, is attached to a spring with a force constant of 132 N/m. The object rests upon a frictionles
Arada [10]

Answer:

See below

Explanation:

a)  Spring force at release =  k * d = 132 N/m * .120 m = 15.84 N

b) F = ma

   15.84 = (.660 kg)(a)     a = 24 m/s^2

c) Toward the left ....the object is accelerated to the left

7 0
2 years ago
Is it possible for a distance versus-time graph to be a vertical line?
Feliz [49]
If time is the x axis and distance is the y axis then yes, in the case that time is going by but distance remains the same.
4 0
3 years ago
Read 2 more answers
What is the net force on charge placed at the center of square of length 1m? All charges have same magnitude of 2 micro coulomb.
Masja [62]

Answer:

Electric Field intensity is zero.

The reason for that is:

All charges are placed at equal distances from the center of the square and have same magnitude and sign. This means they will exert equal and opposite forces on the test charge at the center. Net force will become Zero.

5 0
3 years ago
How much force is required to accelerate an 1800 kg truck 3 m/s
ANEK [815]

Answer:

5,400 Newtons.

Explanation:

Force = 1,800 kg * 3 m/s^2 = 5,400 kg*m/s^2 = 5,400 N

7 0
3 years ago
Estimate the frequency of vibration of your arm.
Natali5045456 [20]

Answer:

0.7945 Hz

Explanation:

Data provided in the question:

Length of the arm = 0.59 m

Since the center of mass lies at about \frac{2}{3} of its length

Thus,

Length of the simple pendulum = \frac{2}{3} × 0.59 m = 0.3933 m

Now,

Frequency of vibration, f = \frac{1}{2\pi}\sqrt\frac{g}{l}

Thus,

we have,

Frequency of vibration for the arm = \frac{1}{2\pi}\sqrt\frac{9.8}{0.3933}

or

Frequency of vibration for the arm = 0.7945 Hz

5 0
3 years ago
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