If they are Conductive medals then yes.
They do attract or push away, cause sometimes they love each other or hate each other. x'D lol
Answer:
<em><u>solution</u></em>
<em>3</em><em>0</em><em>8</em><em>=</em><em>2</em><em>0</em><em> </em><em>swings</em><em> </em>
<em> </em><em>?</em><em>:</em><em>:</em><em>:</em><em> </em><em>=</em><em>1</em>
<em>(</em><em> </em><em>3</em><em>0</em><em>8</em><em>×</em><em>1</em><em>)</em><em>÷</em><em>2</em><em>0</em>
<em>3</em><em>0</em><em>8</em><em>÷</em><em>2</em><em>0</em>
<em>1</em><em>5</em><em>4</em><em>÷</em><em>1</em><em>0</em>
<em>=</em><em>1</em><em>5</em><em>.</em><em>4</em>
<em>=</em>15.4
Answer:
V₂= 1 L
Explanation:
Given that
Volume occupies V₁= 6 L
Initial pressure = P₁
Initial temperature = T₁
The final pressure =P₂ = 2 P₁
Final volume =V₂
Final temperature = T₁/3
As we know that equation for ideal gas
P V = m R T
P=pressure, V=volume, T=temperature
m=mass ,R=gas constant
Now from mass conservation
6 = 3 x 2 V₂
V₂= 1 L
So the final volume will be 1 L
Answer:
23 m/s downward
__________________________________________________________
<em>Taking the downward direction as positive</em>
<u>We are given:</u>
Initial velocity of the marble (u) = 0 m/s
Time interval (t) = 2.3 seconds
Final velocity (v) = x m/s
<u>Solving for the Final velocity:</u>
<u>Acceleration of the Marble:</u>
We know that gravity will make the marble accelerate at a constant acceleration of 10 m/s
<u>Final velocity:</u>
v = u + at [First equation of motion]
x = 0 + (10)(2.3) [replacing the given values]
x = 23 m/s
Hence, after 2.3 seconds, the marble will move at a velocity of 23 m/s in the downward direction
Answer:
Explanation:
In this case, since the charged particle moves in circular motion, the centripetal force is equivalent to the magnetic force.
