Explanation:
It is given that, the height of a certain tower is 862 feet i.e to reach on the ground the object should travel, s = 862 feet
The distance traveled by a freely falling object is given by :
t = 7.34 seconds
So, the object will take 7.34 seconds to fall to the ground from the top of the building. Hence, this is the required solution.
It's difficult to measure that because it's hard to make sure it is only a uniform layer of gas in whatever you're measuring it in
The velocity of the second glider after the collision is 4.33 m/s rightward.
<h3>
Velocity of the second glider after the collision</h3>
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
- m₁ is mass of first glider
- m₂ is mass of second glider
- u₁ is initial velocity of first glider
- u₂ is initial velocity of second glider
- v is the final velocity of the gliders
(2)(1) + (3)(5) = (2)(2) + 3v₂
17 = 4 + 3v₂
3v₂ = 17 - 4
3v₂ = 13
v₂ = 13/3
v₂ = 4.33 m/s
Thus, the velocity of the second glider after the collision is 4.33 m/s rightward.
Learn more about linear momentum here: brainly.com/question/7538238
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Remember that the speed of a wave is the product of both the wavelength and the frequency of the wave.
First convert the units to m and then multiply the values to calculate its propagation or wave speed.
C = lambda • frequency.
