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mars1129 [50]
3 years ago
15

The diagram shows a 15-kg box resting on a wedge which has an angle of inclination of 30° and a coefficient of friction of 0.15.

Find the value of the vector Fg.
Physics
2 answers:
telo118 [61]3 years ago
6 0
We calculate first for the normal force, Fn, which is equal to the product of the force and the cosine of the given angle,
                                         Fn = (15 kg)(9.8 m/s²)(cos 30°)
                                          Fn = 127.30 N
Then, to calculate for the Fg, we multiply the normal force by the given coefficient.
                                         Fg = (127.30 N)(0.15) = 19 N
The nearest value is letter A. 
lara31 [8.8K]3 years ago
6 0
The correct answer is B. 147.15 N
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Here we verify that a car hitting from behind will not generate a force to the sides, but will generate a force in the same direction that the car moves, forward.

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3 years ago
If the cart has potential energy of 5,000 J and kinetic energy of 2,750 J. How much mechanical energy does the cart have?
Dahasolnce [82]

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sukhopar [10]

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Viktor [21]

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-26 m/s.

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Hello,

In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:

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Regards.

3 0
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