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LuckyWell [14K]
3 years ago
14

Solve for x. x^2 - 2x + 1 = 0x 2 −2x+1=0

Mathematics
2 answers:
JulsSmile [24]3 years ago
6 0
Im pretty sure the answer is 1.000781
hope it helps
please mark as brainliest
Maksim231197 [3]3 years ago
6 0
Solve for x over the real numbers:
x^2 - 2 x + 1 = 0

Write the left hand side as a square:
(x - 1)^2 = 0

Take the square root of both sides:
x - 1 = 0

Add 1 to both sides:

Answer:  x = 1
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What is the midpoint of the x-intercepts of f(x) = (x – 4)(x + 4)? (0,0) (0,4) (–4,0) (2,0)
forsale [732]

Answer:

The midpoint of the x-intercepts of the function is (0, 0)

Step-by-step explanation:

Notice that since the function comes in factor form, we know that its roots (which are actually the intercepts the function has with the x-axis) are: x = 4 and x = -4 (the x-values for which the function renders zero).

These two points are equidistant from the origin of coordinates (0, 0), and therefore the midpoint of these x-intercepts is (0, 0).

6 0
3 years ago
If someone helps me with dis ill give u brainliest​
jolli1 [7]

Answer:

4 different answers

Step-by-step explanation:

1.

[(24/3) + (5*2^2)] = 28

2.

[(3 + 5) * 2^2 )]/24 = 32/24 = 4/3

3.

[(24/3 + 5)*2^2] = 52

4.

[(3 + 5*2^2)/24] = 23/24

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3 years ago
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Please help me!!!!!!!!!!
azamat

Answer:

oh sorry i dont know that im grade six sorry

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