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3 years ago

Solve for x. x^2 - 2x + 1 = 0x 2 −2x+1=0

Mathematics

2 answers:

JulsSmile [24]3 years ago

6 0

Im pretty sure the answer is 1.000781
hope it helps
please mark as brainliest

Maksim231197 [3]3 years ago

6 0

Solve for x over the real numbers:
x^2 - 2 x + 1 = 0

Write the left hand side as a square:
(x - 1)^2 = 0

Take the square root of both sides:
x - 1 = 0

Add 1 to both sides:

Answer: x = 1

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Use the intercept formula x a + y b = 1, where a and b are the x- and y-intercepts, respectively, to find an equation of a line

Eddi Din [679]

Just plug em in
5x + 8b = 1
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3 0

3 years ago

PLEASE HELP ASAP HURRY

bulgar [2K]

Answer: The amount she pays for admission

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem

Damm [24]

Answer:

a) P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) = 0,7120 or 71,2 %

c) P(C) = 0,2055 or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )! ⇒ C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2 ⇒ C ( 24,4) = 10626

TE = 10626

Splitting the group of tanks in two 6 with h-v and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3) = 6 * 18! / 3!*15! = 18*17*16*15!/15!

FE = 4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2 = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120 or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2 ⇒ FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055 or P(C) = 20,55 %

5 0

3 years ago

Andrew wants 1/4 of a pizza Brice wants 2/9 and Collins wants 5/12 .How many slices would the pizza need to be cut into?

EastWind [94]

The answer is 36. because 12x3=36, 9x4=36, and 4x9=36, so it is the least common denominator

7 0

3 years ago

Read 2 more answers

A baseball is hit and its height is given by h = 29.4t – 4. 9t^2, where h is the

ioda

Answer:

44.1m

Step-by-step explanation:

we are given a quadratic function which represents the height and time of a baseball

$\displaystyle h = 29.4t - 4.9 {t}^{2}$

we want to figure out maximum height of

the baseball

since the given function is a quadratic function so we have a parabola

which means figuring out the maximum height is the same thing as figuring out the maximum y coordinate (vertex)

to do so we can use some special formulas

recall that,

$\displaystyle \rm t= \frac{ - b}{ 2a}$

$\displaystyle H_{\text{max}}=f(t)$

notice that, our given function is not in standard form i.e

$\displaystyle f(x) = a {x}^{2} + bx + c$

let's make it so

$\displaystyle h = - 4.9 {t}^{2} + 29.4t$

therefore we got

our <em>a</em> is -4.9 and <em>b </em>is 29.4

so substitute:

$\displaystyle\rm t= \frac{ -( 29.4)}{ 2 \cdot - 4.9}$

remove parentheses and change its sign:

$\displaystyle\rm t= \frac{ -29.4}{ 2 \cdot - 4.9}$

simplify multiplication:

$\displaystyle\rm t= \frac{ -29.4}{ - 9.8}$

simplify division:

$\displaystyle \: t = 3$

so we have figured out the time when the baseball will reach the maximum height

now we have to figure out the height

to do so

substitute the got value of time to our given function

$\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot {3}^2$

simplify square:

$\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot 9$

simplify mutilation:

$\displaystyle H_{\text{max}}=88.2-44.1$

simplify substraction:

$\displaystyle H_{\text{max}}=44.1$

hence,

the maximum height of the baseball is 44.1 metres

4 0

2 years ago

Read 2 more answers