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2 years ago

Multiply (6 + 2i)(6 - 2i)

Mathematics

2 answers:

Shtirlitz [24]2 years ago

8 0

Answer:

4i^2 - 36

Step-by-step explanation:

(6+2i)(6-2i)

(2i * 2i) = 4i^2

(2i * -6) = -12i

(2i * 6) = 12i

(-6 * 6) = -36

combine like terms

4i^2 - 36

Aleksandr-060686 [28]2 years ago

3 0

Answer:

Step-by-step explanation:

(6 + 2i)(6 - 2i)=40

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In a metal fabrication process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n

Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, $\bar{x}$ = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

Degree of freedom = n - 1 = 15

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314$

$14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)$

is the required confidence interval for the true mean length of rods.

3 0

3 years ago

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Please help me !!!!!

romanna [79]

Answer:

3/8

Step-by-step explanation:

If 1 and 3 are odd numbers then all you have to do is count the number of 1 and 3's(3). then count the number of numbers (8).

3 0

2 years ago

Order of operations with integers<br><br> Please help solve with steps:<br><br> 3+4 x (-5)

lilavasa [31]

Answer:

-17

Step-by-step explanation:

3 + 4(-5)

= 3-20

= -17

Hope this helps!

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2 years ago

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What is the constant of variation if y varies inversely as x and y = 3 when x = 6? PLZ HELP ME I DONT UNDERSTAND

mojhsa [17]

Answer:

k = 18

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = 3 when x = 6, that is

3 = $\frac{k}{6}$ ( multiply both sides by 6 )

18 = k

The constant of variation is k = 18

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2 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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3 years ago

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