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7nadin3 [17]
2 years ago
7

The solar cells I have supply 34 watts per square meter. 100 square meters will supply 100 x 34 = 3400 watts which is 3.4 kilowa

tts. How many square meters of solar panels would you need to 2 kilowatts?
Mathematics
2 answers:
777dan777 [17]2 years ago
7 0

Answer:

<u>The correct answer is 58.82 square meters of solar panels will be needed to supply 2 kilowatts</u>

Step-by-step explanation:

Solar cell energy supply = 34 watts per square meter

Therefore, 100 square meters will supply 3400 watts which is 3.4 kilowatts.

How many square meters of solar panels would you need to 2 kilowatts?

Total energy = 2 kilowatts = 2,000 watts

Number of square meters = Total energy/Solar cell energy supply

Number of square meters = 2,000/34

<u>Number of square meters = 58.82</u>

<u>It will be necessary 38.82 square meters of solar panels to supply 2 kilowatts</u>

ehidna [41]2 years ago
3 0

<u>Answer: </u>

2000 watts or 2 kilowatts will be supplied in 58.82 sq. meters

<u>Explanation:</u>

1 kilowatt = 1000 watts

Therefore, 2 kilowatts = 2 * 1000 \text { watts } = 2000 watts

According to question,

3400 watts are supplied in 100 square meters

Then, according to the principle of unitary method:

2000 watts will be supplied in:\frac{100 * 2000}{3400} \mathrm{sq} . \text { meters }

\frac{100 * 2000}{3400}=58.82 \mathrm{sq.} \text { meters }

Hence, 2000 watts or 2 kilowatts will be supplied in 58.82 sq. meters

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Step-by-step explanation:

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Finally, look at y=log to the base 4 of (x-2).  The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right.  Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.

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The function is graphed as shown below

Part A:

We use the formula - \frac{b}{2a} to find the vertex of the function. A quadratic function of the form of a x^{2} +bx+c and equating this form to the given function - x^{2} +20x-75, we have
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Part B:

We can find solution to this equation by factorising

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