One half of the sum of 7 and F minus the product of 6 and Q?

1 answer:

8 0

This is how you would write the statement:
$\frac{1}{2}(7+F)-(6*Q)$

You could also write it like this, if the one-half applies to everything:
$\frac{1}{2} ((7+F)-(6*Q))$

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What is the mean of 72,73,86,59,75,58,50,55

Rashid [163]

Mean is the average. To find the mean of a data set, you have to add all the numbers and divide the sum by the amount of numbers you added.

<em>In this equation, you have 8 numbers. That means you will be dividing by 8. </em>

The first thing you need to do is add all the numbers. Add:

$72+73+86+59+75+58+50+55 = \bf 528$

Now that you have added all the numbers and got the sum, divide by 8. Remember that you will be dividing by 8 since you added 8 numbers.

Divide:

$528 \div 8 = \bf 66$

The mean is 66

<em>If you have any questions, feel free to ask in the comments! :)</em>

7 0

2 years ago

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HELP ME ASAP PLEASE!!

lilavasa [31]

Answer:

a=45 b=65

Step-by-step explanation:

You know that all the angle measures of a triangle add to 180. So the equation would be angle a + angle b + 70 = 180. Subsitute and simplify and you get 16x -2 + 70 = 180. Subtract 70 from 180 to get 16x -2=110 add 2 to get 16x =110. Divide each side by 16 to gte x=7. Subsitute x = 7 into the equations for angle a and angle b to get the answers above

4 0

2 years ago

Write an<br> algebraic expression for:<br> the sum of a squared and 6

Darina [25.2K]

The answer is a² + 6. "Sum of a squared and 6" means you square a value and then add 6 to it.

8 0

2 years ago

A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first r

Kryger [21]

The probability of occurrence for the events A, B and C is; 1/4.

<h3>What is the probability of occurrence of.the described events?</h3>

For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;

Event A = 2/8 = 1/4.

For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;

Event B = 2/8 = 1/4.

For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;

Event C = 2/8 = 1/4.