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kupik [55]
3 years ago
11

One half of the sum of 7 and F minus the product of 6 and Q?

Mathematics
1 answer:
ankoles [38]3 years ago
8 0
This is how you would write the statement:
\frac{1}{2}(7+F)-(6*Q)

You could also write it like this, if the one-half applies to everything:
\frac{1}{2} ((7+F)-(6*Q))
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Help me out please will mark you BRAINLIST
melisa1 [442]

Answer:

D. 18.68

Step-by-step explanation:

27\div \frac{5}{3}-6+53\times (\frac{2}{5})^2

Applying PEMDAS as order of operations.

Solving the exponents first [(\frac{2}{5})^2=\frac{4}{25}]

=27\div \frac{5}{3}-6+53\times \frac{4}{25}

Multiplying [53\times \frac{4}{25}=8.48]

=27\div \frac{5}{3}-6+8.48

Dividing [27\div \frac{5}{3}=16.2]

=16.2-6+8.48

Adding and subtracting.

=18.68

6 0
3 years ago
Alvin is 15 years younger than Elga. The sum of their ages is 25. What is Elga’s age
Fynjy0 [20]
Elga is 20 years old and Alvin would be 5. Hope this helped.
4 0
3 years ago
Find the length of side BC. Round your answer to the nearest tenth.
Arturiano [62]

Answer:

2.5

Step-by-step explanation:

(6)cos(65)

7 0
2 years ago
(1 pt)
LekaFEV [45]
B it is going to give you the answer
4 0
4 years ago
The amount of time a certain brand of light bulb lasts is normally distribued with a mean of 1800 hours and a standard deviation
DedPeter [7]

Answer: 68% of light bulbs last between 1765 hours and 1835 hours.

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

From the information given, the mean is 1800 hours and the standard deviation is 35 hours.

1 standard deviation = 1 × 35 = 35

1800 - 35 = 1765 hours

1800 + 35 = 1835 hours

Therefore, 68% of light bulbs last between 1765 hours and 1835 hours.

6 0
3 years ago
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