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REY [17]
2 years ago
9

219 is what percent of 146?

Mathematics
2 answers:
dexar [7]2 years ago
7 0
....................The answer is 150
k0ka [10]2 years ago
5 0

Answer:

150

Step-by-step explanation:

100%/ x% = 219/ 416

Cross multiply

x = 150 %

219 is 150% of 416

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How many solutions exist for the system of equations graphed below?
Grace [21]

Answer: None

Step-by-step explanation: They are parallel and would never intersect

7 0
3 years ago
Read 2 more answers
What are some Examples of similar triangles or polygons that you may see in the real world?
Fofino [41]

Answer:

You can see objects, nd buildings that have those shapes, and roof tops.

Step-by-step explanation:


8 0
2 years ago
Bank A charges a monthly service fee of $5.00 and a per-check fee of $0.05,
Anna007 [38]

Answer:

2 + .05x = 1.5 +.1x

.5 = .05x

x =10 is number when costs are equal

So the 11th check makes Bank A cheaper

Step-by-step explanation:

3 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
What are the corresponding steps used to find the product of (2x + 1)(x + 1)?
Margarita [4]

Answer:

(2 x +1) ( x + 1)  = 2 x² + 3 x + 1

Step-by-step explanation:

The steops used to find the product of (2 x + 1) (x + 1) are

 =( 2 x )× x + (2 x) × 1 + x + 1

 = 2 x² + 2 x + x + 1

 = 2 x² + 3 x + 1

4 0
3 years ago
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