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REY [17]
3 years ago
9

219 is what percent of 146?

Mathematics
2 answers:
dexar [7]3 years ago
7 0
....................The answer is 150
k0ka [10]3 years ago
5 0

Answer:

150

Step-by-step explanation:

100%/ x% = 219/ 416

Cross multiply

x = 150 %

219 is 150% of 416

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Pllsss help
torisob [31]

Answer:

[8.6,oo)

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.
inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

  polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

  for any given point.

# In polar coordinates there is an infinite number of coordinates

   for a given point. For instance, the following four points are all

   coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

  the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

   or degrees.

- To convert from Cartesian Coordinates (x , y) to

  Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the y-axis is

  y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

•      the coordinates of the foci are (0 , ± c),  

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is  y²/a² - x²/b² = 1

∴  y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0
3 years ago
1. Five times a whole number x is subtracted from 62 The result is less than 40
grandymaker [24]

Answer:

Step-by-step explanation:

1.  Symbolically, we get:  62 - 5x < 40

2.  y - 7.3 < 3.4.  Solve for y by adding 7.3 to both sides, obtaining:

     y < 10.7    This is both the 'range' and the 'solution'

3a)      4b =  9b + 45, or -5b = 45, or b = -9

3b)      5a + 10 = 4a - 4

Combining like terms results in a = -14

6 0
3 years ago
Which are characteristics of the graph of the function f(x) = (x + 1)2 + 22 Check all that apply.
Sunny_sXe [5.5K]

Answer: The domain is all real numbers

I can't say that the y intercept is 3 because when you distribute,

f(x) = (x + 1)2 + 22 \\ f(x) = 2x + 2 + 22 \\ f(x) = 2x + 24

It seems like the y intercept is 24.

5 0
3 years ago
One number is 6 times another. The sum of their reciprocal id 14/3. Find the numbers.
nydimaria [60]
Let
x-------> one number
y--------> another number

we know that
x=6y--------> equation 1
(1/x)+(1/y)=14/3-----> (x+y)/xy=14/3-----> 3*(x+y)=14xy-----> equation 2

<span>I substitute 1 in 2
</span>3*(6y+y)=14(6y)y------> 21y=84y²-----> y=0.25
x=6y-----> x=6*0.25-----> x=1.5

the answer is
the numbers are 1.5 and 0.25

5 0
4 years ago
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