Answer:
x=30
Step-by-step explanation:
3(x+2)^3/5 +3=27
Subtract 3 from each side
3(x+2)^3/5 +3-3=27-3
3(x+2)^3/5 =24
Divide by 3
3/3(x+2)^3/5 =24/3
(x+2)^3/5 =8
Take everything to the 5/3 power to get rid of the exponent on the left side
(x+2)^3/5 ^ 5/3=8 ^ 5/3
Remember that a^b^c = a^ (b*c)
(x+2)^(3/5 * 5/3)=8 ^ 5/3
(x+2)=8 ^ 5/3
Replace 8 with 2^3
(x+2)=2^3 ^ 5/3
Remember that a^b^c = a^ (b*c)
(x+2)=2^(3 * 5/3)
x+2 = 2^5
x+2 = 32
Subtract 2 from each side
x+2-2 = 32-2
x=30
Question:
Find the sum of the first six terms of a geometric progression.
1,3,9,....
Answer:
Step-by-step explanation:
For a geometric progression, the sum of n terms is:
In the given sequence:
So:
Answer:
answer is D
Step-by-step explanation:
2^4=16
16+(16-12)=20
over
(6+9)/(7-4)
15/3=5
so the new equation is 20/5=4
Answer:
2x^2- 8x
Step-by-step explanation:
2x(x-4)
distribute; multiply parenthesis by 2 x
2x * x-2x *4
calculate products
2x^2- 8x
