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4 years ago

Evaluate the solution:

Physics

1 answer:

slavikrds [6]4 years ago

3 0

Answer:

Tension, T = 105.09 N

Explanation:

Given that,

Length of the string, l = 0.33 m

Mass of the string, $m=0.3\times 10^{-3}\ kg$

Fundamental frequency, f = 440 Hz

The expression for the speed in terms of tension is given by :

$v=\sqrt{\dfrac{T}{(m/l)}}$

$v^2=\dfrac{Tl}{m}\\\\T=\dfrac{v^2m}{l}\\\\T=\dfrac{(340)^2\times 0.3\times 10^{-3}}{0.33}\\\\T=105.09\ N$

So, the tension in the string is 105.09 N.

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nikdorinn [45]

Answer:

See the answers below.

Explanation:

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Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

$P=V*I$

where:

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V = voltage [V]

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$I = P/V\\I=160/240\\I=0.67 [amp]$

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

$V=I*R$

where:

V = voltage [V]

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Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

$P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R$

$60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]$

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

$R = 133.66 + 225\\R = 358.67 [ohms]$

7 0

3 years ago

Four hundred seventy joules of heat are removed from a heat reservoir at a temperature of 470 K. What is the entropy change of t

11111nata11111 [884]

Answer:

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Explanation:

Given data

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To find

Entropy change ΔS

Solution

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We have take heat value Q as negative because the heat is removed from heat reservoir

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