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Katen [24]
3 years ago
6

Although I am solid, I am so light that I can float in any liquid listed on the chart. What am I?-----

Chemistry
1 answer:
evablogger [386]3 years ago
3 0

Answer:

I know that Aerogel is the lightest metal in existence, but I don't think it would help much with your answer. I mean you can give it a try?

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PLEASE HELP. !!
scoray [572]

Answer:

Potential energy = 441 N

Explanation:

Given:

Mass M = 15 kg

Height = 3 m

Find:

Potential energy

Computation:

Potential energy = mgh

Potential energy = (15)(9.8)(3)

Potential energy = 441 N

8 0
2 years ago
To what volume should you dilute 55 mL of 12 M stock HNO3 solution to obtain a 0.145 HNO3 solution?
velikii [3]

Answer:

4552 mL

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 55 mL

Molarity of stock solution (M₁) = 12 M

Molarity of diluted solution (M₂) = 0.145 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

12 × 55 = 0.145 × V₂

660 = 0.145 × V₂

Divide both side by 0.145

V₂ = 660 / 0.145

V₂ ≈ 4552 mL

Thus, the volume of the diluted solution is 4552 mL

7 0
3 years ago
2. C + S → CS2 <br><br>Reaction Type:​
Lyrx [107]
Combination or synthesis reaction
5 0
3 years ago
HURRY PLEASE HELP
Dahasolnce [82]

Answer:

A

Explanation:

its A

facts o.o

7 0
3 years ago
Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur
Assoli18 [71]

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

Heat absorbed = 885 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

8 0
3 years ago
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