<span>Since these molecules are all non-polar, the only intermolecular force of attraction will be London dispersion forces. Since these increase by the size of the molecule, the boiling points will decrease in the same order:
Parafin > Heptadecane > hexane > 2,2-dimethylbutane > propane
For these two, hexane > 2,2-dimethylbutane, dispersion forces are greater in a molecule which is longer and unbranched compared to one which is branched and more compact.</span>
Answer:
Explanation:
It is easier if you convert the kelvin temperature into Celsius degrees:
- ºC = T - 273.15 = 150 - 273.15 = -123.15ºC
Now, you know that that is a very cold temperature. Thus, may be the oxygen is not gas any more but it changed to liquid . . . or solid?
You must search for the boiling point and melting (freezing) point of oxygen in tables or the internet. At standard pressure (about 1 atm) they are:
- Melting point: −218.79 °C,
- Boiling point: −182.962 °C
That means that:
- below -218.79ºC oxygen is solid (not our case).
- between -218.79ºC and -182.962ºC oxygen is liquid (not our case)
- over -182.962ºC oxygen is a gas. This is our case, because -123.15ºC is a higher temperature than -182.962ºC.
Hence, <em>the state of matter of oxygen at 150K</em>, and standard pressure, is gas.
Answer: Option (b) is the correct answer.
Explanation:
The given chemical reaction shows that hydrogen cyanide acid has been added to water which results in the formation of hydronium ion and cyanide ion.
Also, when we add a base like sodium hydroxide (NaOH) to HCN then it will help in accepting a proton (
) from hydrogen cyanide. As a result, formation of 
anion will be rapid and easy.
This will make the system not to do any extra work. So, amount of work done by system will decrease.
Thus, we can conclude that out of the given options, add solid NaOH to the reaction (assume no volume change) will decrease the amount of work the system could perform.
Answer:
a. Rate = k [H2O+-OH][Br-]
Explanation:
For a reaction:
nA+xB→C+D
The rate of the reaction is:
Rate = [A]ⁿ[B]ˣ
Now, in a mechanism, the rate of the reaction depends of the slow step. In the problem:
H2O+-OH + Br-→ HOBr + H2O
And the rate is:
<h3>a. Rate = k [H2O+-OH][Br-]
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