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Radda [10]
3 years ago
13

Bonds between carbon and oxygen are more polar than bonds between sulfur and oxygen. nevertheless, sulfur dioxide (so2) exhibits

a dipole moment while carbon dioxide (co2) does not. explain. (problem 1.31)
Chemistry
1 answer:
Zepler [3.9K]3 years ago
3 0

Bonds between carbon and oxygen are more polar than bonds between sulfur and oxygen. nevertheless, sulfur dioxide (SO₂) exhibits a dipole moment while carbon dioxide (CO₂) does not because of the difference in their shape, CO₂ is having linear geometry thus exhibit zero dipole moment while SO₂ is having bent shape thus exhibit dipole moment. So, despite the fact that bonds between carbon and oxygen are more polar than bonds between sulfur and oxygen. nevertheless, sulfur dioxide (SO₂) exhibits a dipole moment while carbon dioxide (CO₂) does not.

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A student increases the temperature of a 673 cm^3 balloon from 275 K to 460 K.
Kruka [31]

Answer:

1125.75 cm³

Explanation:

We are given;

Initial volume; V1 = 673 cm³

Initial temperature; T1 = 275 K

Final temperature; T2 = 460 K

From Charles law, we can find the new volume from;

V1/T1 = V2/T2

V2 = (V1 × T2)/T1

V2 = (673 × 460)/275

V2 = 1125.75 cm³

8 0
2 years ago
Suppose we have a 12.2 L sample containing 0.50 mol oxygen gas at a pressure of 1 atm and a temperature of 25 degrees celcius. I
snow_lady [41]

Answer:

c. 8.1 L

Explanation:

Given that:-

Moles of oxygen gas = 0.50 mol

According to the reaction shown below as:-

3O_2\rightarrow 2O_3

3 moles of oxygen gas on reaction gives 2 moles of ozone

Also,

1 mole of oxygen gas on reaction gives 2/3 moles of ozone

So,

0.50 mole of oxygen gas on reaction gives \frac{2}{3}\times 0.50 moles of ozone

Moles of ozone = 0.3333 mol

Pressure = 1 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25.0 + 273.15) K = 298.15 K  

Volume = ?

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 0.3333 mol × 0.0821 L.atm/K.mol × 298.15 K  

⇒V = 8.1 L

6 0
2 years ago
Please anwser this question will me thanked
Nataly_w [17]
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Can anyone here help me with chemistry
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The answer is 20g N2
5 0
2 years ago
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