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3 years ago

When the pH of a solution is 12.83, what is [H +]?

Chemistry

1 answer:

inn [45]3 years ago

4 0

Answer:

B.9.710-11M

Explanation:

<h3>plss tell me if im wrong</h3>

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Write equations for the following: (b) an addition reactionbetween cyclohexene and Cl₂;

lorasvet [3.4K]

The required equation for an addition reaction between cyclohexene and Cl2 .

Cyclohexene + Cl2 → 1,2-dichlorocyclohexane

What is addition reaction ?

it is type of reaction in which one molecule combines with another molecule to form larger molecules .

addition reaction types are electrophilic , nucleophilic and free radical addition reaction .

<h3>What is free radical addition reaction ?</h3>

it is type of addition reaction where functional group is added to a compound through a free radical intermediate .

The free radical addition reaction involves chain initiation , chain propagation and chain termination .

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2 years ago

Atoms in a liquid have _________ energy than atoms in a solid, so the easiest way to change a solid to a liquid is to add ______

Nitella [24]

More,
heat/ energy,
melting point

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3 years ago

Muscle physiologists study the accumulation of lactic acid [ch3ch(oh)cooh] during exercise. food chemists study its occurrence i

Drupady [299]

The provided information are:
volume of 0.85 M lactic acid = 225 ml
volume of 0.68 M sodium lactate = 435 ml
Ka of the lactate buffer = 1.38 x 10⁻⁴
The equation for dissociation of lactic acid is:
CH₃CH(OH)COOH(aq) + H₂O ⇄ CH₃CH(OH)COO⁻(aq) + H₃O⁺(aq)
The pH of buffer is calculated from Henderson-Hasselbalch equation, which is:
pH = pKa + log $\frac{[conjugated base]}{[Acid]}$
pKa = - log Ka = - log (1.38 x 10⁻⁴) = 3.86
The number of moles of lactic acid and lactate are as follows:
n (Lactic acid) = 225 ml x 0.85 mmol/ml = 191.25 mmol
n (Lactate) = 435 ml x 0.68 mmol/ml = 295.8 mmol
The number of moles of lactic acid and lactate in total volume of the solution:
[CH₃CH(OH)COOH] = n (lactic acid) / 660 ml = 191.25 mmol / 660 ml = 0.29 M
[CH₃CH(OH)COO⁻] = n (lactate) / 660 ml = 0.45 M
pH = 3.86 + log $\frac{0.45 M}{0.29 M}$ = 3.86 + 0.191 = 4.05
So the pH of given solution is 4.05

7 0

3 years ago

A sample of carbon dioxide is contained in a 250.0 mL flask at 0.930 atm and 15.4 °C. How many molecules of gas are in

Yanka [14]

Answer:

We are given:

Volume (V) = 0.25 L

Pressure (P) = 0.93 atm

Temperature (T) = 15.4°C OR 288.4 K

<u>Solving for the number of moles of CO₂:</u>

From the ideal gas equation:

PV = nRT

replacing the variables

0.93 * 0.25 = n (0.082)(288.4)

n = 0.00983 moles

<u>Number of molecules:</u>

Number of moles= 0.00983

number of molecules in 1 mole = 6.022 * 10²³

Number of molecules in 0.00983 moles = 0.00983 * 6.022 * 10²³

Number of molecules = 5.91 * 10²¹

8 0

3 years ago

Jason ran 5/7 of the distance around the school track sara ran 4/5 of Jason distance what fraction of the total distance around

FrozenT [24]

Let x represent the total distance around the track
Jason's distance: (5/7)x
Sara ran (4/5) of Jason's distance,
so she ran (4/5)*(5/7)x = (4/7)x
Sara ran 4/7 of the total distance

7 0

3 years ago