The solution is as follows:
K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106
The molar mass of isoborneol/borneol is 154.25 g/mol
Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol
Use the ICE approach
borneol → isoborneol
I 0.0972 0.0486
C -x +x
E 0.0972 - x 0.0486 + x
Total moles = 0.1458
Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P
0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832
Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
Answer:
No One is going to answer all this because it hard to type it all in her. its easy to search it up
Explanation:
<span>Mass=25.7gm
dimensions,
l=2.3cm
b=4.01cm
h=1.82cm
Thus,Density=Mass/Volume=m/lbh=25.7/2.3*4.01*1.82 g cm-3</span>
Explanation:
Br2 + S2O32- + 5H2O –> 2Br- + 2SO4 + 10H+ + 6e
Answer:
1,816 L
Explanation:
Molar concentration or molarity is a way to express the concentration of a chemical in terms of moles of substances per liter of solution.
To obtain the liters of this solution you must convert moles/L to g/L with formula weight (FW), thus:
0,1107 mol of KCl / L × (74,6 g / mol) = 8,258 g of KCl / L.
It means that in one liter you have 8,258 g of KCl. Thus, 15,00 g of KCl are contained in:
15,00 g × (1 L / 8,258 g) = 1,816 L
I hope it helps!
