Here, we are required to determine the pressure of the sample of gas trapped in the open-tube mercury manometer shown below if Atmospheric pressure is 767 mmHg and pressure head, h = 8.9 cmHg.
- The pressure of the sample of gas trapped in the open-tube mercury manometer is;. 856 mmHg
According to the question;
- The atmospheric pressure is 767 mmHg
- The gauge pressure is 8.9 cmHg = 89mmHg.
The absolute pressure, P(abs);
is given mathematically as;
Absolute pressure = Atmospheric pressure + gauge pressure.
P(abs) = P(atm) + P(gauge)
P(abs) = 767mmHg + 89mmHg.
P(abs) = 856 mmHg.
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