Answer:
102.0 g/mol.
Explanation:
Aluminum oxide or Al2O3 is a chemical compound composed of 3 Oxygen and 2 aluminum atoms. Naturally, it is present in the form of mineral corundum in crystalline polymorphic forms. It holds significant importance in the preparation of Aluminium metal that is used as a refractory material.
To calculate the molar mass of Aluminum oxide, we will add the molar mass of 2 Al and 3 O atoms.
Since molar mass of Al is: 26.98 g
Molar mass of O is: 16.00 g
Molar mass of Al2O3
= (26.98)2 + (16.00) 3
= 53.96 + 48
= 101.96 g/mol
Since it is mentioned in question to round off the answer upto 4 significant figures, it will make the answer: 102.0 g/mol.
Hope it help!
Mass of Magnesium nitrate produced : 593.2 g
<h3>Further explanation</h3>
The reaction equation is the chemical formula of reagents and product substances
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
2HNO₃ + Mg(OH)₂ → Mg(NO₃)₂ + 2H₂0
mol HNO₃ = 8
From the equation, mol ratio of HNO₃ : Mg(NO₃)₂ = 2 : 1, so mol Mg(NO₃)₂ :
Mass Mg(NO₃)₂(MW=148,3 g/mol) :
Answer:
56.17% is percent composition of Sb in the molecule
Explanation:
Percent composition is the percent in mass of each element present in a particular molecule.
In SbF₅, there is 1 mole of Antimony -Molar mass: 121.76g- per 5 moles of fluorine -Molar mass: 19g/mol-. In a basis of 1 mole, the mass of Sb and F is:
<em>Mass Sb:</em>
1mol * (121.76g/mol) = 121.76g
<em>Mass F:</em>
1 mol SbF₅ = 5 moles F * (19g / mol) = 95g
<em>Total mass:</em>
121.76g + 95g = 216.76g
And percent composition of Sb:
121.76g / 216.76g * 100 =
<h3>56.17% is percent composition of Sb in the molecule</h3>
The answer is 33.33 %
The explanation:
According to the reaction equation:
MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)
we can see that 1 mole of MCO3 will produce → 1 mole of CO2
-Now we need o get number of mole of CO2:
and when we have 0.22 g of CO2, so number of mole = mass / molar mass
moles = 0.22 g / 44 g/mol = 0.005 mole
∴ moles of Mg = moles of CO2 = 0.005 mole
∴ mass of Mg = moles * molar mass
= 0.005 * 84 /mol = 0.42 g
∴ Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100
= 33.33 %
Iodine hexafluoride is the chemical name
