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AysviL [449]
3 years ago
10

The following graphs show average temperature data for two locations. Both locations have the same elevation. What is most likel

y true about the locations?
A. Location A is farther from the equator than location B.
B. Location A is closer to the equator than location B.
C. Location B is located farther inland than location A.
D. Location A is in the northern hemisphere, and location B is in the southern hemisphere.

Chemistry
1 answer:
enot [183]3 years ago
4 0

Answer:

A

Explanation:

Location b is warmer meaning its closer to the equator and i got it write

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vaieri [72.5K]

i believe the answer is a Brainiest plz

6 0
3 years ago
0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati
erastova [34]

Answer:

[Ag^{+}]=4.2\times 10^{-2}M

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]

[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}

Now,

Ag_{2}CrO_4(s) \leftrightharpoons  2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}

[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

                       

7 0
3 years ago
HELP, 40 POINTS !!
Lemur [1.5K]

1. Solubility

2. Heat 100g of water to 35 degrees C. Add 37 grams of mystery salt.

3. If all the salt dissolves, it's KCl. If not, it's KNO3.

4 0
4 years ago
Unknown # 29
sveticcg [70]

Answer:

I think it's a sulphate ion, because when you add hydrochloric acid to it it produces bubbles and when you add barium chloride it then produces a white precipitate.its formula is SO4

I hope this helps

8 0
3 years ago
A particular oral contraceptive contains 0.038 mg of ethinyl estradiol in each pill. The formula of this compound is C20H24O2. H
Ray Of Light [21]

<u>Answer:</u> The number of molecules of ethinyl estradiol present in one pill are 7.71\times 10^{16}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethinyl estradiol = 0.038 mg = 3.8\times 10^-5}g    (Conversion factor: 1 g = 1000 mg)

Molar mass of ethinyl estradiol (C_{20}H_{24}O_2)=[(20\times 12)+(24\times 1)+(2\times 16)]=296g/mol

Putting values in above equation, we get:

\text{Moles of ethinyl estradiol}=\frac{3.8\times 10^{-5}g}{296g/mol}=1.28\times 10^{-7}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 1.28\times 10^{-7}mol of ethinyl estradiol will contain = (1.28\times 10^{-7}\times 6.022\times 10^{23})=7.71\times 10^{16} number of molecules

Hence, the number of molecules of ethinyl estradiol present in one pill are 7.71\times 10^{16}

5 0
3 years ago
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