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ziro4ka [17]
3 years ago
15

A cruise ship sailed for 9 hours at a speed of 18 miles per hour. How far did the cruise ship sail?

Mathematics
2 answers:
tiny-mole [99]3 years ago
7 0
The answer is D because you would multiply time traveled by distance traveled in a period

maria [59]3 years ago
4 0
9 x 18 = 162 So that makes D the correct option
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Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up
Artyom0805 [142]

Answer:

In the long run, ou expect to  lose $4 per game

Step-by-step explanation:

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.

Assuming X be the toss on which the first head appears.

then the geometric distribution of X is:

X \sim geom(p = 1/2)

the probability function P can be computed as:

P (X = n) = p(1-p)^{n-1}

where

n = 1,2,3 ...

If I agree to pay you $n^2 if heads comes up first on the nth toss.

this implies that , you need to be paid \sum \limits ^{n}_{i=1} n^2 P(X=n)

\sum \limits ^{n}_{i=1} n^2 P(X=n) = E(X^2)

\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+(\dfrac{1}{p})^2        ∵  X \sim geom(p = 1/2)

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+\dfrac{1}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p+1}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-p}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-\dfrac{1}{2}}{(\dfrac{1}{2})^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{4-1}{2} }{{\dfrac{1}{4}}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{3}{2} }{{\dfrac{1}{4}}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ 1.5}{{0.25}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =6

Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6

= $4

∴

In the long run, you expect to  lose $4 per game

3 0
4 years ago
Find the surface area of a wooden box full of shape is of a cube and if the age of the box is 4 cm
Sav [38]
All you have to do is multply 4 by all the sides of the cube
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3 years ago
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For Each Data Set, Determine the median, the first and third Quartiles, and the interquartile Range.
stiks02 [169]
1. First of all arrange the data set in either ascending or descending order.
12, 19, 24, 26, 31, 38, 53.  N = 7 (number of data items)
Median position = 1/2(N + 1)th item = 1/2(7 + 1)th item = 1/2(8)th item = 4th item = 26
First quatile = 1/4(N + 1)th item = 1/4(7 + 1)th item = 1/4(8)th item = 2nd item = 19
Third quatile = 3/4(N + 1)th item = 3/4(7 + 1)th item = 3/4(8)th item = 6th item = 38
Interquatile range = Third quartile - first quatile = 38 - 19 = 19
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An oblique square prism is shown. An oblique square prism is shown. The square has side lengths with a measure of x. The distanc
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Answer:

Your answer is C.) x2(x – 2) cubic units

On EDG

Step-by-step explanation:

Just took the test

6 0
3 years ago
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The sidewalks on both sides of Peach St, are parallel. One sidewalk can be modeled by the equation 2x - y=-1. Which equation cou
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Answer:

I believe the answer would be d

Step-by-step explanation:

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