All categories

3 years ago

Statistics... Help!

Mathematics

1 answer:

Leokris [45]3 years ago

4 0

Answer:

a) 0.5233 = 52.33% probability of picking someone who has the disease.

b) 0.9091 = 90.91% probability of picking someone who tests negative, given that he/she did not have the disease

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

a) What is the probability of picking someone who has the disease.

132 + 25 = 157 people have the disease

132 + 25 + 13 + 130 = 300 people total

157/300 = 0.5233

0.5233 = 52.33% probability of picking someone who has the disease.

b) What is the probability of picking someone who tests negative, given that he/she did not have the disease?

143 people did not have the disease.

130 tested negative. So

130/143 = 0.9091

0.9091 = 90.91% probability of picking someone who tests negative, given that he/she did not have the disease

You might be interested in

Need math help pls!!

SVEN [57.7K]

Answer:

Step-by-step explanation:

The facts we have are the height of the small lighthouse is 8, and the base is 2.5. The base of the big lighthouse is 10.

The factor between the base of the big lighthouse and small lighthouse is 4 (10/2.5).

If we apply this to the height, 8x4 = 32

4 0

3 years ago

Solve x4 - 11x2 + 18 = 0.

lara31 [8.8K]

Answer:

x=√2, x=-√2, x= 3 and x=-3

Step-by-step explanation:

We need to solve the equation x^4 - 11x^2+18=0

We can replace x^4 = u^2 and x^2 = u

So, the equation will become

u^2 -11u+18 = 0

Factorizing the above equation:

u^2 -9u-2u+18 =0

u(u-9)-2(u-9)=0

(u-2)(u-9)=0

u=2, u=9

As, u = x^2, Putting back the value:

x^2 =2 , x^2 =9

taking square roots:

√x^2 =√2 ,√x^2=√9

x=±√2 , x = ±3

so, x=√2, x=-√2, x= 3 and x=-3

6 0

2 years ago

Read 2 more answers

Please help with math

kykrilka [37]

Answer:

2nd option, x > 1.10

Step-by-step explanation:

$7e^{2x}-5 > 58$

Add 5 to both sides,

$7e^{2x}-5+5 > 58 +5\\7e^{2x} > 63$

Divided both sides by 7,

$\frac{7e^{2x}}{7} > \frac{63}{7}$

$e^{2x} > 9$

Apply Exponent Rule,

$2x > 2ln(3)$

$\frac{2x}{2} > \frac{2ln(3)}{2}$

x > ln(3) or x > 1.09861

Learn more about logarithms here: brainly.com/question/12049968

5 0

1 year ago

*^%Brainliest 15 pounds Question 5 (2 points)

galben [10]

Answer:

Step-by-step explanation:

Separate into two parts

$\frac{4xy^{3} }{2xy^{2} } + \frac{8x^{2} {y}^{5} }{2x {y}^{2} }$

Simplify:

This is for the first fraction

$\frac{4x {y}^{3} }{2x {y}^{2} } = (4 \div 2)(x \div x)( {y}^{3} \div {y}^{2} )$

$2(1)( {y}^{3 - 2} )$

$2{y}$

Now for the second fraction:

$\frac{8 {x}^{2} {y}^{3} }{2x {y}^{2} } = ( 8 \div 2)( {x}^{2} \div x)( {y}^{5} \div {y}^{2} )$

$4( {x}^{2 - 1} )( {y}^{5 - 2} )$

$4x {y}^{3}$

Add both parts together

$2y + 4x {y}^{3}$

To turn this into the said formula, that would become:

$2 {x}^{0} {y}^{1} + 4 {x}^{1} {y}^{3}$

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1

4 0

3 years ago

what is the probability that the first roll is an even number and the second roll is a number greater than 4?

dalvyx [7]

Multipcation i think

3 0

3 years ago

Read 2 more answers