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Mashcka [7]
3 years ago
15

Statistics... Help!

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

a) 0.5233 = 52.33% probability of picking someone who has the disease.

b) 0.9091 = 90.91% probability of picking someone who tests negative, given that he/she did not have the disease

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

a) What is the probability of picking someone who has the disease.

132 + 25 = 157 people have the disease

132 + 25 + 13 + 130 = 300 people total

157/300 = 0.5233

0.5233 = 52.33% probability of picking someone who has the disease.

b) What is the probability of picking someone who tests negative, given that he/she did not have the disease?

143 people did not have the disease.

130 tested negative. So

130/143 = 0.9091

0.9091 = 90.91% probability of picking someone who tests negative, given that he/she did not have the disease

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Answer:

\textbf{Hello!}

\Longrightarrow2^2+2z=0

\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}

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\Longrightarrow =\sqrt{2^2}

\Longrightarrow=2

\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}

\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}

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\Longrightarrow =\frac{-4}{2\cdot \:1}

\Longrightarrow =\frac{-4}{2}

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x=0,\:x=-2\Longleftarrow

\underline{HOPE ~IT~HELPS}

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