yes i think because i think so
In doing this you can use the factoring method to do this faster. Start by dividing both sides by two to simplify the equation. X^2 now equals 100.
You can move 100 to the other side of the equation so that x^2-100=0. You can now factor and solve using the zero product property.
x^2-100=0
(x+10)(x-10) = 0
x equals 10 and -10.
Answer:
i think that the answer would be but im not 100% sure
Step-by-step explanation:
Answer:
option B (28/52)
Step-by-step explanation:
from probability
P(A∪B)=P(A)+P(B)-P(A∩B)
where
P(A∪B) = probability that event A or B happen
P(A∩B) = probability that event A and B happen simultaneously
P(A) = probability that event A happen
P(B) = probability that event B happen
the probability that the card is special or red
P( special or red)= P(special) + P(red) - P( special and red)
since
P(special)= 4/52
P(red) = 26/52
P( special and red) = 2/52
therefore
P( special or red)= 4/52 + 26/52 - 2/52 = 28/52
P( special or red)= 28/52
(option B)
