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8_murik_8 [283]
3 years ago
9

In looking at the bolded atoms in the answer choices, which pair consists of molecules having the same geometry? hints in lookin

g at the atoms in the answer choices, which pair consists of molecules having the same geometry? ch2o and ch3oh co2 and so2 ch2ccl2 and ch2ch2 pcl3 and bf3

Chemistry
2 answers:
Alchen [17]3 years ago
8 0

Answer:


               1,1-Dichloroethene (CH₂CCl₂) and Ethene (H₂CCH₂) have same molecular geometries.


Explanation:

                      The molecular geometries of all molecules are drawn below. Among these molecules four molecules contains four atoms which has same geometry. These are Boron in BF₃, Carbon in CH₂O, both carbon atoms CH₂CCl₂ and both carbon atoms H₂CCH₂. All specified elements in these molecules have same geometry (Trigonal Planar). 

While, the overall geometry of only two molecules is same. Those two are CH₂CCl₂ and H₂CCH₂ because in these molecules all carbon atoms have Trigonal Planar Geometry. Hence, we can confirm that among given compounds this pair has same geometry.

Rzqust [24]3 years ago
5 0
Correct Answer: CH2CCI2 and CH2CH2.

Reason:
Structure of compound depends on the hybridization of central atom. In both of the above molecules (i.e. CH2CCL2 and CH2CH2). Central atom i.e. carbon is sp^2 hybridized.  Thus 3 hybridized orbitals of 'C' is involved in sigma bonding. Further, these orbitals are placed spatially at an angle of 120^{0}. The un-hybridized 2pz orbital of 'C' is involved in pi-bonding. Due to this, both of the above molecules possess a triangular planner geometry. 
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What is the mass of 6.02 x 1022 atoms of Xenon? HELP!!!!!
il63 [147K]
So 6.02*10^22 is avogadro constant, which is the amount of atoms in one mole. If you look Xenon up in the periodic table you will find it's mass given <span>131,293, which is grams per 1 mole. 

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8 0
3 years ago
When two or more substances combine, but each keeps it own properties,the new combination is called a (an)
Harman [31]

The new combination is called a mixture.

In mixtures, since the substances are not chemically combined together, they still remain their own physical and chemical properties, and can be separated by simple physical methods such as filtration or distillation.

On the other hand, if the two or more substances are combined where they get new properties, the new combination will be called a compound.  They cannot be separated by physical methods, but chemical methods such as heating or electrolysis.


7 0
3 years ago
How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation? 2HBr(aq)+
Mkey [24]

Full Question:

A flask containing 420 Ml of 0.450 M HBr was accidentally knocked to the floor.?

How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation?

2HBr(aq)+K2CO3(aq) ---> 2KBr(aq) + CO1(g) + H2O(l)

Answer:

13.1 g K2CO3 required to neutralize spill

Explanation:

2HBr(aq) + K2CO3(aq) → 2KBr(aq) + CO2(g) + H2O(l)

Number of moles = Volume * Molar Concentration

moles HBr= 0.42L x .45 M= 0.189 moles HBr

From the stoichiometry of the reaction;

1 mole of K2CO3 reacts  with 2 moles of HBr

1 mole = 2 mole

x mole = 0.189

x = 0.189 / 2 = 0.0945 moles

Mass = Number of moles * Molar mass

Mass = 0.0945 * 138.21  = 13.1 g

3 0
3 years ago
8. If I have 34 grams of FeO, how many grams of Oxygen were synthesized?<br>Fe + O2 → Feo​
krek1111 [17]

Answer:

34 gram of FeO produced 8 gram of oxygen.

Explanation:

Given data:

Mass of FeO = 34 g

Mass of oxygen = ?

Solution;

Chemical equation:

2FeO → 2Fe + O₂

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 34 g /71.8 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of FeO with oxygen:

             FeO       :       O₂

                2         :        1

                0.5      :      1/2 × 0.5 = 0.25

Mass of oxygen:

Mass = number of moles × molar mass

Mass =  0.25 mol × 32 g/mol

Mass = 8 g

So 34 gram of FeO produced 8 gram of oxygen.

8 0
3 years ago
Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.
Akimi4 [234]
Answer is: <span>the empirical formula of the hydrocarbon is CH</span>₂.<span>
Chemical reaction: C</span>ₓHₐ + O₂ → xC + a/2H₂O.<span>
m(CO</span>₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.

6 0
4 years ago
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