So in order it goes from: 0.6, 0.02, 0.007
Answer:
x = 100
Step-by-step explanation:
![57 \degree + (x + 23) \degree = 180 \degree..(straight \: line \: \angle s) \\ (x + 80) \degree = 180 \degree \\ x + 80 = 180 \\ x = 180 - 80 \\ \huge \red{ \boxed{x = 100}}](https://tex.z-dn.net/?f=57%20%5Cdegree%20%2B%20%28x%20%2B%2023%29%20%5Cdegree%20%3D%20180%20%5Cdegree..%28straight%20%5C%3A%20line%20%5C%3A%20%20%5Cangle%20s%29%20%5C%5C%20%28x%20%2B%2080%29%20%5Cdegree%20%3D%20180%20%5Cdegree%20%5C%5C%20x%20%2B%2080%20%3D%20180%20%5C%5C%20x%20%3D%20180%20-%2080%20%5C%5C%20%20%5Chuge%20%5Cred%7B%20%5Cboxed%7Bx%20%3D%20100%7D%7D)
Speed of the boat = u
speed of the current = v
in downstream,
u - v = 105/5
u - v = 21
in upstream
u + v = 105/7
u + v = 15
add both equations
2u = 36
u = 18
v = -3
so
speed of the boat = 18 km/h
speed of the current = 3 km/h
Answer: t= 13.2 seconds
Step-by-step explanation:
The quadratic function for ball's height in terms of time t is given as
s(t)= -16t² +192t + 256
Now we want to find out the time at which the ball hits the ground.
When the ball hits the ground, the height of the ball will become zero so in the above equation we can put s(t)=0
0= -16t² +192t + 256
or 16t² -192t - 256 = 0
Solving this quadratic equation, we have
t= 13.211 and t= -1.211
Since time can't be negative so
t= 13.2 seconds
Answer:
x = 5
y = 2
Step-by-step explanation:
-3x + 3y = -9
3y = 3x - 9
Equation 1. <em><u>y = x - 3</u></em>
-3x + y = 7
Equation 2. <u><em>y = 3x + 7</em></u>
So, put number 1 equation to number 2's y :
x - 3 = 3x + 7
x -3x = 7 + 3
-2x = 10
2x = 10
x = 10/2
x = 5
And, put x, which is 5 , to the any equation to figure out the y.
This time, I'll use equation number 1.
y = 5 - 3
y = 2