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slega [8]
3 years ago
12

If 15 workers did a job is 8 hours, how long would it take 5 workers to do half of this job?

Mathematics
2 answers:
babymother [125]3 years ago
8 0
Since 15 workers did 8 hours of work, the total amount of work needed is 120 hours. Half of this job would be 60 hours. Then divide this amount by the 5 workers doing the job. This would make the job 12 hours
yarga [219]3 years ago
5 0
J=15w*8h=120(worker*hours)

5h=120/2

5h=60

h=12 hours
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Vikki [24]

Answer:

x+3y=21 in standard form

8 0
3 years ago
Read 2 more answers
What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!
Radda [10]

Two main facts are needed here:

1. The logarithm \log x, regardless of the base of the logarithm, exists for x>0.

2. The square root \sqrt x exists for x\ge0.

(in both cases we're assuming real-valued functions only)

By (2) we know that \sqrt{2x-1} exists if 2x-1\ge0, or x\ge\dfrac12.

By (1), we know that \log(\sqrt{2x-1}+3) exists if \sqrt{2x-1}+3>0, or \sqrt{2x-1}>-3. But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require x\ge\dfrac12, so the function has domain \left[\dfrac12,\infty).

To determine the range, we need to know that, in their respective domains, \sqrt x and \log x increase monotonically without bound. We also know that x=\dfrac12 at minimum, at which point the square root term vanishes, so the least value the function takes on is \log3. Then its range would be [\log3,\infty).

3 0
3 years ago
Of 5
aniked [119]

Answer:

Krutika

Step-by-step explanation:

Lets convert each person's typing rate to words/min.

Krutika:

80 minutes = 6000 words

1 minute = (6000/80) words

              = 75 words

Typing Rate: 75 words / min

Mark:

60 minutes = 4200 words

1 minute = (4200/60) words

              = 70 words

Typing Rate: 70 words / min

David:

90 minutes = 5850 words

1 minute = (5850/90) words

              = 65 words

Typing Rate: 65 words / min

From the above, we can see Krutika has the fastest rate of words per minute.

3 0
2 years ago
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
If p(a) = 0.50, p(b) = 0.60, and p(a intersection
bogdanovich [222]
Use the identity P(A &cup; B) = P(A)+P(B)-P(A &cap; B)

P(A)=0.50
P(B)=0.60
P(A &cup; B) = 0.30
=>
P(A &cup; B) = P(A)+P(B)-P(A &cap; B)
=(0.50+0.60)-0.30
=0.80
5 0
2 years ago
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