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4 years ago

Which lists the elements in order from most conductive to least conductive?

Physics

2 answers:

artcher [175]4 years ago

5 0

Answer:

Answer: potassium (K) germanium (Ge) selenium (Se)

Explanation:

I just took the test, the farther to the right on the periodic table you go the less conductive it gets.

Anna11 [10]4 years ago

3 0

Answer:

Answer: potassium (K) germanium (Ge) selenium (Se)

Explanation:

The most conductive to least conductive is from left to right

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Blackbody radition is white give reasons.?

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Explanation:

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3 years ago

In electric motors and electric generators, which part is responsible for transferring current from the power source to the comm

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3 years ago

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Consider two laboratory carts of different masses but identical kinetic energies and the three following statements. I. The one

kolbaska11 [484]

Answer:

d) I and III only.

Explanation:

Let be $m_{1}$ and $m_{2}$ the masses of the two laboratory carts and let suppose that $m_{1} > m_{2}$ . The expressions for each kinetic energy are, respectively:

$K = \frac{1}{2}\cdot m_{1}\cdot v_{1}^{2}$ and $K = \frac{1}{2}\cdot m_{2}\cdot v_{2}^{2}$ .

After some algebraic manipulation, the following relation is constructed:

$\frac{m_{1}}{m_{2}} = \left(\frac{v_{2}}{v_{1}}\right)^{2}$

Since $\frac{m_{1}}{m_{2}} > 1$ , then $\frac{v_{2}}{v_{1}} > 1$ . That is to say, $v_{1} < v_{2}$ .

The expressions for each linear momentum are, respectively:

$p_{1} = \frac{2\cdot K}{v_{1}} = m_{1}\cdot v_{1}$ and $p_{2} = \frac{2\cdot K}{v_{2}} = m_{2}\cdot v_{2}$

Since $v_{1} < v_{2}$ , then $p_{1} > p_{2}$ . Which proves that statement I is true.

According to the Impulse Theorem, the impulse needed by cart I is greater than impulse needed by cart II, which proves that statement II is false.

According to the Work-Energy Theorem, both carts need the same amount of work to stop them. Which proves that statement III is true.

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3 years ago

You are driving home from school steadily at 97 km/h for 190 km . It then begins to rain and you slow to 60 km/h instantly. You

GarryVolchara [31]

Please delete my answer. I made a mistake

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3 years ago

A 100-turn coil with an average radius of 0.04 m is placed in a uniform magnetic field so that ϕ = 60°. The strength of the fiel

gogolik [260]

Five

This is exactly like your question 2. You need only substitute the given numbers here.

Givens

N = 100 turns
delta B = 0.25
r = 0.04
Area = pi * r^2 = 3.14 * 0.04^2 = 5.02 * 10^-3
Cos 60 = 1/2 = 0.5

Formula

e = N * delta B * Area * cos phi

Solution

e = - 100 * 0.25 * 5.02 * 10^-3 * 0.5

e = 0.0628 = 0.063

Answer

Six

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4 years ago

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