Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
Answer:
6 root 2
Step-by-step explanation:
Pythagous Therom
A^2 = B^2 + C^2
B^2 = C^2 - A^2
B^2 = 36 - (2 Root 3)^2
B^2 = 24
B = 2 root 6
Base x Height / 2 for area of Triangle
2 root 3 x root 24 = 12 root 2
12 root 2 / 2 = 6 root 2
Answer:
c
Step-by-step explanation:
sorry if wrong
First step is to distribute.
-4a^2 - 6a +2 + 3a^2 -3
Combine like terms
-a^2 -6a -1
Answer:
b
Step-by-step explanation:
