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4 years ago

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Which equivalence factor should you use to convert from 3.48 x 1018 atoms of magnesium (Mg) to moles of magnesium? A (1 mol Mg/1

atom Mg) B (1 mol Mg/3.48 x 1018 atoms Mg) C (1 mol Mg/6.02 x 1023 atoms Mg) D (6.02 x 1023 atoms Mg/1 mol Mg)

1 answer:

faltersainse [42]4 years ago

6 0

1242.375Mg=1976Mg located

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A hiker climbs to the top of a mountain at rate of 0.5 me/hr. What are the speed and velocity of the hiker?

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A hiker climbs to the top of a mountain at rate of 0.5 m/hr. The speed of hiker is 1.3 x 10⁻⁴ m/s and the velocity of the hiker is 1.3 x 10⁻⁴ m/s west.

Speed is a scalar quantity. It is used to measure the distance traveled in a period of time. It is represented by -

s = d/Δt

where,

s = speed

d = distance

Δt = change in time

Velocity is a vector quantity. It is used to measure the change in position, that is, displacement over the change in time. It is represented by -

v = Δs / Δt

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v = velocity

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Δt = change in time

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1 year ago

Which of these is a compound A sugar B window cleaner C nitrogen D silver

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What 4 elements did people at ancient greek time believe that all matter is made up?

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4 years ago

Carbon monoxide gas reacts with hydrogen gas to form methanol via the following reaction: CO(g)+2H2(g)→CH3OH(g)CO(g)+2H2(g)→CH3O

zvonat [6]

<u>Answer:</u> The limiting reactant is hydrogen gas and the theoretical yield of methanol is 0.507 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas which follows:

$PV=nRT$ ..........(1)

<u>For carbon monoxide:</u>

We are given:

$P=232mmHg\\V=1.55L\\T=305K\\R=62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Putting values in equation 1, we get:

$232mmHg\times 1.55L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 305K\\\\n=\frac{232\times 1.55}{62.3637\times 305}=0.0189mol$

<u>For hydrogen gas:</u>

We are given:

$P=389mmHg\\V=1.55L\\T=305K\\R=62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Putting values in equation 1, we get:

$389mmHg\times 1.55L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 305K\\\\n=\frac{389\times 1.55}{62.3637\times 305}=0.0317mol$

For the given chemical equation:

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

By Stoichiometry of the reaction:

2 moles of hydrogen gas reacts with 1 mole of carbon monoxide

So, 0.0317 moles of hydrogen gas will react with = $\frac{1}{2}\times 0.0317=0.01585mol$ of carbon monoxide

As, given amount of carbon monoxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrogen gas produces 1 mole of methanol

So, 0.0317 moles of hydrogen gas will produce = $\frac{1}{2}\times 0.0317=0.01585moles$ of methanol

Now, calculating the mass of methanol from equation 1, we get:

Molar mass of methanol = 32 g/mol

Moles of methanol = 0.01585 moles

Putting values in equation 1, we get:

$0.01585mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.01585mol\times 32g/mol)=0.507g$

Hence, the limiting reactant is hydrogen gas and the theoretical yield of methanol is 0.507 grams

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3 years ago

When [2-14c, 15n] glutamate undergoes oxidative degradation in the liver of a rat, in which metabolite atoms will each isotope b

Ksivusya [100]

The question is missing the metabolites:

These are:

A. Urea

B. Succinate

C. Arginine

D. Citrulline

E. Ornithine

F. Aspartate

Check the attached file for the answer.

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