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2 years ago

What's the oxidation number of Li in LiNO3

Chemistry

1 answer:

Studentka2010 [4]2 years ago

4 0

Explanation:

To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.

The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit

The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.

The algebraic sum of all oxidation number of atoms in a neutral compound is zero;

The radical NO₃ has a formal charge of -1;

let the oxidation number of Li = x

x + (-1) = 0

x = + 1

learn more:

Oxidation number brainly.com/question/10017129

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The region in which an electron is likely to be found is known as a(n) ____________.

Zinaida [17]

Answer:

orbital

Explanation:

electrons are found in an orbital

3 0

2 years ago

If the conjugate base of a molecule has a pkb of 1.4, what would you expect the molecule to be?

maw [93]

If the conjugate base of a molecule has a pKb of 1.4, the molecule should be a Weak Acid.

Notice this question gives us the pKb of the molecule, not the pKa. Because of this, the pH scale basically gets reversed, so lower numbers in pKb correlate with stronger bases, and higher numbers in pKb correlate with stronger acids - the exact opposite of the pH scale.

It's important to make sure you completely understand the terms of conjugate base, conjugate acid, pKb, pKa, and how they all relate. It's easy to mix up the meanings of these definitions.

Here are the two other pieces of information you need to know to correctly answer this question:

Strong acids have a weak conjugate base.
Strong bases have a weak conjugate acid.

So if the problem says you have a strong conjugate base, then the molecule must be a weak acid. To illustrate this, think of ammonium, NH4+. Ammonium is a weak acid, but the conjugate base of ammonium is ammonia, NH3, which is a reasonably good base.

Learn more about conjugate base here : brainly.com/question/22514615

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3 0

2 years ago

When are zeros significant in a value ?

ASHA 777 [7]

Answer:

If the zero is between fwo nonzeros

Explanation:

5 0

3 years ago

Read 2 more answers

Carry out the following operations as if they were calculations of experimental results and express each answer in standard nota

Shalnov [3]

Answer:

1. $10.6\; \rm m$ (one decimal place.)

2. $0.79\; \rm g$ (two decimal places.)

3. $16.5\;\rm cm^2$ (three significant figures.)

Explanation:

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

$5.6792\;\rm m$ has four decimal places.
$0.6\; \rm m$ has only one decimal place.
$4.33\; \rm m$ has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: $\rm m$ .)

Therefore:

$\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m$ . (Rounded to one decimal place.)

Similarly:

$\rm 3.70\; \rm g$ has two decimal places.
$2.9133\; \rm g$ has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be $\rm g$ (same as the unit of the two inputs.)

$\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g$ . (Rounded to two decimal places.)

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

$4.51\; \rm cm$ has three significant figures.
$3.6666\; \rm cm$ has five significant figures.

Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be $\rm cm \cdot cm$ , which is occasionally written as $\rm cm^2$ .