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2 years ago

What's the oxidation number of Li in LiNO3

Chemistry

1 answer:

Studentka2010 [4]2 years ago

4 0

Explanation:

To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.

The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit

The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.

The algebraic sum of all oxidation number of atoms in a neutral compound is zero;

The radical NO₃ has a formal charge of -1;

let the oxidation number of Li = x

x + (-1) = 0

x = + 1

learn more:

Oxidation number brainly.com/question/10017129

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What are all the intermolecular forces present in a sample of BrF?

yuradex [85]

Answer:

dipole-dipole

Explanation:

Intermolecular forces exists between the molecules of a substance in a particular state of matter.

The type of intermolecular forces present in a substance is determined by the electronegativity difference between the atoms that compose the substance.

There is a non zero electronegativity difference between Br and F hence the molecule is polar and the intermolecular forces between the molecules of BrF are dipole-dipole forces.

4 0

2 years ago

Given the equation: HCl + Na2SO4 → NaCl + H2SO4, if you start with 8 moles of hydrochloric acid, how many grams of sulfuric acid

Simora [160]

Answer:

392g sulfuric acid are produced

Explanation:

Based on the balanced equation:

2HCl + Na2SO4 → 2NaCl + H2SO4

2 moles of HCl produce 1 mole of sulfuric acid

To solve the problem we need to find the moles of sulfuric acid produced based on the chemical equation. Then, using its molar mass -Molar mass H2SO4 = 98g/mol- we can find the mass of sulfuric acid produced:

Moles sulfuric acid:

8mol HCl * (1mol H2SO4 / 2mol HCl) = 4 mol H2SO4

Mass sulfuric acid:

4mol H2SO4 * (98g / mol) =

392g sulfuric acid are produced

4 0

3 years ago

A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo

Liula [17]

Answer: The molar mass of the insulin is 6087.2 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol$

Hence, the molar mass of the insulin is 6087.2 g/mol

8 0

3 years ago

Calculate the molarity of a nitric acid solution if 38 ml of the solution is neutralized by 16 ml of 0.25 M barium hydroxide sol

RUDIKE [14]

Answer:

Explanation:

8 0

2 years ago

What is the standard enthalphy change ΔHo, for the reaction represented above? (ΔHof of C2H2(g) is 230 kJ mol-1; (ΔHof of C6H6(g

wolverine [178]

Answer:

-608KJ/mol

Explanation:

3 C2H2(g) -> C6H6(g)

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= ΔHC6H6 - 3ΔHC2H2

ΔHrxn = 83 - 3(230)

ΔHrxn = -608

6 0

3 years ago