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marishachu [46]
3 years ago
5

If the diameter of a disc is 50 ft, what will be the area of the disc?

Mathematics
2 answers:
olga55 [171]3 years ago
7 0

Hey there! Your answer is:

1,963

Step-by-step explanation:

Please mark Brainliest<3

Artist 52 [7]3 years ago
3 0
Yo I was stuck on this to but it is really simple it’s
1963
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A poster is marked down 35% from an original price of $7.80. What is the sale price?
Julli [10]

Answer:

%5.07

Step-by-step explanation:

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When u round to the nearest hundred thousand the population of the state of North Carolina is 9,800,000. Which could be the exac
rjkz [21]

Answer:

D - 9,848,060

Step-by-step explanation:

In the number 9,848,060 the number 8 is in the hundred thousands place.

The number behind it is 4, which is nor equal to or more than 5, meaning that that the 8 stays the same.

6 0
3 years ago
Hank spend 76% of his monthly salary and saves $270 find his monthly salary
Dimas [21]

Answer:

f $270= the remaining 24% then you want to do 270/24=11.25 Then you want to multiply that by 76 and you will get $855

So $270+$855=24%+76% So his monthly salary was $1,125

If you are still confused do it in reverse! 1,125/100=11.25

11.25•24=270 & 11.25•76=855

270+855=1,125

Step-by-step explanation:

the guy below copied me

4 0
2 years ago
Thirteen is at least the difference of a number v and 1.
Mariulka [41]
13≥v-1 is the formula
4 0
3 years ago
Read 2 more answers
The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

8 0
3 years ago
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