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sdas [7]
3 years ago
9

What did Thomson’s and Rutherford’s experiments have in common? They both used charged particles in their experiments. They both

used emission spectra to discover electron clouds. They both compared the atom to an indivisible sphere. They both discovered electron clouds.
Physics
2 answers:
Triss [41]3 years ago
6 0

Answer:

Both Thomson and Rutherford used charged particles in their experiments.

Explanation:

lozanna [386]3 years ago
5 0
Theo both used charged particles
You might be interested in
Question 10 of 34
labwork [276]

Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.

<h3>What is displacement?</h3>

Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.

Displacement is a vector quantity .its unit is m.

The average velocity on this walk will be;

\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4  \ block /min

Hence option B is correct.

To learn more about displacement refer to the link; brainly.com/question/10919017

#SPJ1

3 0
2 years ago
An object weighs 200N, what is its mass?​
fredd [130]

Answer:

kg

Explanation:

the highr and jebad to kilogram mizans

3 0
2 years ago
Read 2 more answers
You push against a steamer trunk with a force of 750 N at an angle of 25° with the horizontal . The trunk is on a flat floor and
djverab [1.8K]
This means that the horizontal force is 750sin(25°). To be able to move the truck, force applied must be greater than static friction, which equals to its coefficient (0.77) x normal contact force (= weight)

Hence, 750sin(25°) = 0.77mg. m = 750sin(25°)/(0.77g)
3 0
3 years ago
A passenger on a jet airplane claims to be able to walk at a speed in excess of 500 mph. Can this be true?
alexdok [17]

Answer:noo

Explanation:impossible

3 0
3 years ago
A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coeff
Trava [24]

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

4 0
2 years ago
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