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3 years ago

Which gland controls the workings of other endocrine glands? Thyroid, pituitary, adrenal, or thymus

Physics

2 answers:

oksano4ka [1.4K]3 years ago

8 0

Answer is pituitary gland.

In order to stimulate or inhibit the hormones produced by the endocrine glands, signals are sent to these endocrine glands by the hormones secreted by the pituitary gland.

Consider the following example. When a person is stressed in order to stimulate the production of cortisol, the anterior pituitary lobe will release adrenocorticotropic hormone (ACTH).

Scrat [10]3 years ago

6 0

Answer:

pituitary gland.

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A balance uses small metal weights of known mass to determine the mass of a substance. Where would a balance NOT function correc

tatuchka [14]

Answer:

D is the answer.

Explanation:

Just do it.

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3 years ago

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A negatively charged rod is placed near two neutral metal spheres, as shown below. Which statements describe the charging method

grin007 [14]

<h3>Answer;</h3>

<em>The spheres develop opposite charges. </em>
<em>Electrons move from Sphere A to Sphere B. </em>
<em>The spheres are charged through induction.</em>

<h3><u>Explanation;</u></h3>

<u><em>When a negatively charged rod is placed near two neutral metal spheres, the spheres will develop opposite charges, because the neutral metal spheres have both negative and positive charges. </em></u>From the basic law of electrostatics unlike charges attracts and like charges repel.
Thus, <em><u>the sphere will develop opposite charges, electrons will move from Sphere A to sphere B,</u></em> hence we say that the spheres will be charged by induction such that sphere A will acquire a positive charge while sphere B will acquire negative charge.

3 0

3 years ago

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A light ray moving at a 54.3 deg

MrMuchimi

Answer:

$45.25^{\circ}$

Explanation:

Applying Snell's law

$n_1sin\theta_1 = n2*sin\theta_2\\1.33*sin(54.3) = 1.52*sin\theta_2\\sin\theta_2 = 1.33*0.81208353/1.52 = 0.71057\\\theta_2=sin^{-1} (0.71057)\\\theta_2 = 45.25^{\circ}$

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3 years ago

a body weights 28N at a height of 3200km from the earth surface.What will be the gravitational force on that body if its lies on

alekssr [168]

Answer:

The object would weight 63 N on the Earth surface

Explanation:

We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:

$F_G=G\,\frac{M_E\,m}{d^2} \\28\,\,N=G\,\frac{M_E\,m}{9600000^2}$

Now, if the body is on the surface of the Earth, its weight (w) would be:

$F_G=G\,\frac{M_E\,m}{d^2} \\w=G\,\frac{M_E\,m}{6400000^2}$

Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:

$\frac{w}{28} =\frac{9600000^2}{6400000^2} \\\frac{w}{28} =\frac{9}{4} \\\\ \\w=\frac{9\,*\,28}{4}\,\,\,N\\w=63\,\,N \\$

4 0

3 years ago

Please help :( A ray of laser light strikes a glass surface at an angle θa = 22.5° to the normal. What is the angle θb of the re

pshichka [43]

Answer:

Explanation:

We shall apply law of refraction which is as follows

sin i / sinr = μ , where i is angle of incidence , r is angle of refraction and μ is refractive index

here i = θa = 22.5°

r = θb

μ = 1.77

sin22.5 / sinθb = 1.77

.3826 / sinθb = 1.77

sinθb = .216

θb = 12.5 °.

4 0

3 years ago