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3 years ago

Which of the following is a science?

Physics

1 answer:

nikitadnepr [17]3 years ago

3 0

Answer:

astrology

Explanation:

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A man can jump 1.5 m on earth. calculate the approximate

Olegator [25]

Answer:

18 m

Explanation:

G = Gravitational constant

m = Mass of planet = $\rho V$

$\rho$ = Density of planet

V = Volume of planet assuming it is a sphere = $\dfrac{4}{3}\pi r^3$

r = Radius of planet

Acceleration due to gravity on a planet is given by

$g=\dfrac{Gm}{r^2}\\\Rightarrow g=\dfrac{G\rho V}{r^2}\\\Rightarrow g=\dfrac{G\rho \dfrac{4}{3}\pi r^3}{r^2}\\\Rightarrow g=\dfrac{4G\rho\pi r}{3}$

So,

$g\propto \rho r$

Density of other planet = $\rho_p=\dfrac{1}{4}\rho_e$

Radius of other planet = $r_p=\dfrac{1}{3}r_e$

$\dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\rho_p r_p}\\\Rightarrow \dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\dfrac{1}{4}\rho_e\times \dfrac{1}{3}r_e}\\\Rightarrow \dfrac{g_e}{g_p}=12\\\Rightarrow g_p=\dfrac{g_e}{12}\\\Rightarrow g_p=\dfrac{9.8}{12}$

Since the person is jumping up the acceleration due to gravity will be negative.

From kinematic equations we have

$v^2-u^2=2g_es\\\Rightarrow u^2=v^2-2g_es\\\Rightarrow u^2=0-2\times -9.8\times 1.5\\\Rightarrow u^2=2\times 9.8\times 1.5$

On the other planet

$v^2-u^2=2g_ps\\\Rightarrow s=\dfrac{v^2-u^2}{2g_p}\\\Rightarrow s=\dfrac{0-(2\times 9.8\times 1.5)}{2\times -\dfrac{9.8}{12}}\\\Rightarrow s=18\ \text{m}$

The man can jump a height of 18 m on the other planet.

5 0

3 years ago

Suggest at least two reagents other than sodium borohydride that could be used to carry out the reduction of 9-fluorenone to 9-h

vampirchik [111]

For the answer to the question above asking to s<span>uggest at least two reagents other than sodium borohydride that could be used to carry out the reduction of 9-fluorenone to 9-hydroxyfluorene.</span>
<span>1. LiAlH4 in ether
2. H2/Pt
</span>I hope this helps

8 0

3 years ago

When you push an object, it pushes back with an equal and opposite force

Ksju [112]

Answer:

I would say false

Explanation:

Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.

5 0

2 years ago

Which of the following is the name of the process scientists use to gain

harkovskaia [24]