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Illusion [34]
3 years ago
13

An air conditioner operating at steady state maintains a dwelling at 70oF on a day when the outside temperature is 90oF. If the

rate of heat transfer into the dwelling through the walls and roof is 30,000 Btu/h, might a net power input to the air conditioner compressor of 3 hp be sufficient? If yes, determine the coefficient of performance. If no, determine the minimum theoretical power input, in hp.
Physics
1 answer:
torisob [31]3 years ago
8 0
30000 btuh /3413 btuh/kw. = 8.8 kw

8.8 kw/.746 kw/hp = 11.8 hp if COP is 1

11.8/3 hp (COP coefficient of performance) = 3.99 COP

>>>So yes a 3.0 hp compressor with a nominal COP of 4 will handle the 30,000 btuh load.

3.2 to 4.5 is expected COP range for an air cooled heat pump or a/c unit.
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If a cart goes around a turn at 20 km/h ,what remains constant
Vitek1552 [10]

Answer: 4.speed

Explanation:

In this case, we know that the cart remains at a constant 20km/h.

Now, one could say that "the velocity remains constant, because it always is 20km/h"

But remember that velocity is a vector, so this has a direction, and if the cart is going around a turn, then the direction of motion is changing, which tell us that there is acceleration.

But the module of the velocity, the speed, remains constant at 20km/h.

Then the correct option is 4, speed.

7 0
3 years ago
What is electropower​
OLEGan [10]

Answer:

electricity

Explanation:

8 0
3 years ago
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How many paths through which charge can flow would be shown in the circuit diagram of a series circuit?
Natalka [10]

A) one ... same current passes through each cpt


7 0
3 years ago
What is the equivalent resistance of a circuit that contains three 10.0 12
lana66690 [7]

Answer:

Explanation:

The equivalent resistance for three resistors connected in parallel is given as

(1/R)=(1/R₁)+(1/R₂)+(1/R₃)

now we.need to.insert the value of 3 resistances but only 2 are given in the question.

3 0
3 years ago
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1) A force of 157 N is applied to a box 25o above the horizontal. If it is applied over a distance of 14.5 m how much work is do
vfiekz [6]

#1

Work done is given by

W = F.d cos\theta

here we know that

F = 157 N

d = 14.5

\theta = 25^0

now from the above formula

W = (157)(14.5)cos25 = 2063.2 J

#2

By energy conservation

Initial total potential energy of egg = final total kinetic energy of egg

mgh = \frac{1}{2}mv^2

v = \sqrt{2gh}

v = \sqrt{2(9.8)(8.2)}

v = 12.7 m/s

#3

By momentum conservation we know that

m_1v_1 = (m_1 + m_2)v

215(9.5) = (215 + 19.7) v

v = \frac{215 (9.5)}{215 + 19.7}

v = 8.7 m/s

#4

by momentum conservation we know that

m_1v_1 + m_2v_2 = (m_1 + m_2) v

let direction of velocity of Jay Z car motion is positive direction

now we will say

1100(-20) + 1475v = (1100 + 1475)(7)

1475 v = 2575(7) + 1100(20)

v = 27.14 m/s

Yes Jay Z is overspeeding as his speed is more than speed limit

#5

Tension force in the string will be centripetal force

so here we can say

T = \frac{mv^2}{R}

here we know that

m = 0.63 kg

v = 7.8 m/s

R = 0.23 m

T = \frac{0.63 (7.8)^2}{0.23}

T = 166.6 N

6 0
3 years ago
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