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Aliun [14]
2 years ago
9

What is the IUPAC name for the compound shown below? ch3ch2ch2cnhch2ch3

Chemistry
2 answers:
antoniya [11.8K]2 years ago
6 0

Answer:

The name is Hexan-3-imine

Explanation:

The systematic name is formed by a prefix, which indicates the number of atoms of  carbon that contains the molecule, and a suffix, which indicates the class of compound  organic in question.

You must first look for the chain  main, which is the chain with the highest amount of carbons. In this case the chain main contains six carbons. This means that the prefix used is Hex-

This case is an alkane (they have only single- bonds between carbons and hydrogen), so you use de suffix -ane

The carbon atoms of the main chain are numbered starting  at the end closest to branching, so that the  carbons with branches have the lowest possible number. In this case the branching is -NH, is in the position 3 and the name is imine.

So, knowing all this, you can name the compound like <u><em>Hexan-3-imine</em></u>

Nataly_w [17]2 years ago
3 0

We need the  IUPAC name of the given compound.

The IUPAC name is: Hexan-3-imine.

The molecule has six carbon atoms in its skeleton. C=NH bond is attached to the skeleton at 3-position.

The functional group present in this molecule is imine (C=NH).

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A. Controlled variable

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a controlled variable or a constant variable is a variable that doesnt change during an experiment

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The ion formed by an atom of sulfur when it gains two electrons is called a:
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Answer:

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If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction?
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If the value of kc at 25oc is 3.7108, and the equilibrium concentrations for n2 and h2 are 0.000105 m and 0.0000542 m, respectiv
frez [133]

Equation of decomposition of ammonia:

N2+3H2->2NH3

Euilibrium constant:

Kc=(NH3)^2/((N2)((H2)^3))

As concentration of N2=0.000105, H2=0.0000542

so equation will become:

3.7=(NH3)^2/(0.000105)*(0.0000542)^3

NH3=√(3.7*0.000105*(0.0000542)^3)

NH3=7.8×10⁻⁹

So concentration of ammonia will be 7.8×10⁻⁹.

5 0
3 years ago
Complete orbital diagrams (boxes with arrows in them) to represent the electron configuration of valence electrons of carbon bef
kramer

Answer:

Explanation:

Before Hybridization => C: 1s²<u> ⇵</u> 2s²<u>⇵</u> 2p₋₁<u>↑</u> 2p₀<u>↑</u> 2p₊₁<u>∅</u>

After Hybridization => C: 1s² 2sp¹ 2sp¹ 2p₀¹2p₊₁¹ => 2 hybrid orbitals and 2 unhybridized p-orbitals at the n=2 energy level.

3 0
3 years ago
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