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3 years ago

What is the IUPAC name for the compound shown below? ch3ch2ch2cnhch2ch3

Chemistry

2 answers:

antoniya [11.8K]3 years ago

6 0

Answer:

The name is Hexan-3-imine

Explanation:

The systematic name is formed by a prefix, which indicates the number of atoms of carbon that contains the molecule, and a suffix, which indicates the class of compound organic in question.

You must first look for the chain main, which is the chain with the highest amount of carbons. In this case the chain main contains six carbons. This means that the prefix used is Hex-

This case is an alkane (they have only single- bonds between carbons and hydrogen), so you use de suffix -ane

The carbon atoms of the main chain are numbered starting at the end closest to branching, so that the carbons with branches have the lowest possible number. In this case the branching is -NH, is in the position 3 and the name is imine.

So, knowing all this, you can name the compound like <u><em>Hexan-3-imine</em></u>

Nataly_w [17]3 years ago

3 0

We need the IUPAC name of the given compound.

The IUPAC name is: Hexan-3-imine.

The molecule has six carbon atoms in its skeleton. C=NH bond is attached to the skeleton at 3-position.

The functional group present in this molecule is imine (C=NH).

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A certain substance has a heat of vaporization of 70.83 kJ / mol. 70.83 kJ/mol. At what Kelvin temperature will the vapor pressu

lana66690 [7]

Answer:

The answer to the question is

The temperature at which the vapor pressure will be 5.00 times higher than it was at 331 K is 353.0797 K.

Explanation:

To solve the question, we make use of the Clausius-Clapeyron equation as follows

$ln(\frac{P_2}{P_1}) = \frac{d_{vap}H}{R} (\frac{1}{T_1} -\frac{1}{T_2} )$

Where P₁ = Initial pressure

P₂ = Final pressure

T₁ = Initial temperature = 331 K

T₂ = Final temperature

dvapH = ΔvapH = Heat of vaporization = 70.83 kJ / mol.

R = Universal gas constant = 8.3145. J K⁻¹ mol⁻¹

We are required to find the temperature when P₂ = 5 × P₁

Therefore we have

$ln(\frac{5*P_1}{P_1}) = \frac{70.83}{8.3145} (\frac{1}{331} -\frac{1}{T_2} )$ = $ln(5) = 8518.853 (\frac{1}{331} -\frac{1}{T_2} )$ or T₂ = $\frac{1}{\frac{1}{331} -\frac{ln(5)}{8518.853} }$ = 353.0797 K

The vapor pressure be 5.00 times higher than it was at 331 K when the temperature is raised to 353.0797 K.

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4 years ago

Calculate the concentration of H3O+ of a solution if the concentration of OH- at 25°C is 3.8 × 10-5 M and determine if the solut

sergejj [24]

Answer:

[H₃O⁺] = 2.63×10⁻¹⁰ M

As pH = 9.57, the solution is basic

Explanation:

We must know this knowledge:

[OH⁻] . [H₃O⁺] = 1×10⁻¹⁴

3.8×10⁻⁵ . [H₃O⁺] = 1×10⁻¹⁴

[H₃O⁺] = 1×10⁻¹⁴ / 3.8×10⁻⁵ → 2.63×10⁻¹⁰ M

Let's determine the pH to state if the solution is acidic or basic

pH < 7 → acidic ; pH > 7 → basi

pH = - log [H₃O⁺]

pH = - log 2.63×10⁻¹⁰ → 9.57

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3 years ago