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Aliun [14]
3 years ago
9

What is the IUPAC name for the compound shown below? ch3ch2ch2cnhch2ch3

Chemistry
2 answers:
antoniya [11.8K]3 years ago
6 0

Answer:

The name is Hexan-3-imine

Explanation:

The systematic name is formed by a prefix, which indicates the number of atoms of  carbon that contains the molecule, and a suffix, which indicates the class of compound  organic in question.

You must first look for the chain  main, which is the chain with the highest amount of carbons. In this case the chain main contains six carbons. This means that the prefix used is Hex-

This case is an alkane (they have only single- bonds between carbons and hydrogen), so you use de suffix -ane

The carbon atoms of the main chain are numbered starting  at the end closest to branching, so that the  carbons with branches have the lowest possible number. In this case the branching is -NH, is in the position 3 and the name is imine.

So, knowing all this, you can name the compound like <u><em>Hexan-3-imine</em></u>

Nataly_w [17]3 years ago
3 0

We need the  IUPAC name of the given compound.

The IUPAC name is: Hexan-3-imine.

The molecule has six carbon atoms in its skeleton. C=NH bond is attached to the skeleton at 3-position.

The functional group present in this molecule is imine (C=NH).

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For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
ladessa [460]

<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

4 0
3 years ago
Какая масса хлора и какое количество вещества необходимо для реакции с 12г магния при получении хлорида магния?
Naddika [18.5K]
Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль  m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg  Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции  с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г.  магния потребуется 11,2 л. хлора.
7 0
3 years ago
You have identified a substance to be solid in nature. which characteristics will justify your identification?
weeeeeb [17]
This question includes four answer choices: A. definite volume, highest molecular motion, highest kinetic energy B. indefinite volume, least molecular motion, highest kinetic energy C. definite volume, least molecular motion, lowest kinetic energy D. definite volume, no molecular motion, lowest kinetic energy Solids do not have the highest molecular motion (on the contrary they have the least molecular motion), so you can discard option A. Solids have a definite volume and the highest kinetic energy (given that they have the least molecular motion), so you discard option C. Molecules always have a vibrational motion, so you discard option D. Option C, have only characteristics that correctly describes a solid: definite volume, least molecular motion, lowest kinetic energy. Therefore, the answer is the option C. <span /><span>
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4 0
3 years ago
Read 2 more answers
Chemistry is the definition​
KIM [24]

Answer:

the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

Explanation:

Hope this helps. :)

8 0
4 years ago
If 28 ml of 5.4 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?
Ainat [17]

A reaction between acid and base to form water and salt is known as neutralization reaction. It is a double replacement reaction.  

The reaction between H_2SO_4 and NaHCO_3 will be:

H_2SO_4 + NaHCO_3 \rightarrow Na_2SO_4 + CO_2 + H_2O

The balanced reaction is:

H_2SO_4 + 2NaHCO_3 \rightarrow Na_2SO_4 + 2CO_2 + 2H_2O

Volume of H_2SO_4 = 28 mL (given)

Since, 1 L = 1000 mL

So, 28 mL = 0.028 L

Molarity of H_2SO_4 = 5.4 M (given)

Molarity = \frac{number of moles of solute}{Volume of solution in Liters}   -(1)

Substituting the values in equation (1):

5.4 mol/L = \frac{number of moles of H_2SO_4}{0.028 L}

number of moles of H_2SO_4 = 5.4 mol/L\times0.028 L

number of moles of H_2SO_4 = 0.1512 mol

From the balanced reaction between H_2SO_4 and NaHCO_3, 2 moles of NaHCO_3 reacts with 1 mole of H_2SO_4.

Molar mass of NaHCO_3 = 84.007 g/mol

Mass of NaHCO_3 needed:

0.1512 mol H_2SO_4 \times \frac{2 mole NaHCO_3}{1 mole H_2SO_4}\times \frac{84.007 g}{1 mole NaHCO_3} = 25.404 g

Hence, the required amount of NaHCO_3 is 25.404 g.


7 0
3 years ago
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