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Tju [1.3M]
3 years ago
8

If the volume of a gas container at 32 degrees Celsius changes from 1.55 L to 755 mL, what will the final temperature be?

Chemistry
1 answer:
QveST [7]3 years ago
4 0
So to solve this you need to know Charles’s law which is: V1/T1=V2/T2. Where T1 and V1 is the initial volume and Temperature and V2 and T2 is the temperature and volume afterwards. So first plug in the numbers you are given. V1= 1.55L T1= 32C° V2= 755mL T2=?. Since your volumes are two different units you change 755mL to be in L so that would be 0.755 L. And since your temp isn’t in Kelvin you do 273+32= 305K°. You then would rearrange your equation to solve for T2 which is V2T1/V1. Then you plug in your numbers (0.755L)(305K)/1.55L. Then you solve and would be 148.5645161 —> 1.49 x 10^2 K
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Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.
lidiya [134]
First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

<span>Concentration of [OH]</span>⁻<span> in solution:
</span>
[ OH⁻ ] = 10 ^{-pOH}

[ OH⁻ ]  = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !


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nadya68 [22]

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Formula

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Where “n” is the number of half lives

To find "n" for 27 hours

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put values in equation 2

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Mass after 27 hr

Put values in equation 1

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6 0
3 years ago
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