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irina1246 [14]
3 years ago
15

Please help! what’s the value of x? 8 56 12 62

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
4 0
The value of x is 56
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the first term of an arthimetic sequence is 42 the rule an= an-1 +8 can 1 can be used explain how to write explict rules
Svet_ta [14]

Answer:

34 + 8n

Step-by-step explanation:

a₁ = 42

a_{n} = a_{n-1} + 8

a₂ = a₁ + 8    = 42 + 8   = 50

a₃ = a₂ + 8   = 50 + 8 = 58

a₄ = a₃ + 8 =   58 + 8  = 66

Arithmetic sequence: 42, 50 , 58 , 66, ......

a₁ = 42 ; d = 8

a_{n} = a₁ + d(n-1)

    = 42 + 8(n - 1)

    = 42 + 8n - 8

   = 34 + 8n

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2 years ago
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What is another name for the height of the pyramid?
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3 years ago
How many possibilities are there if you are creating a 4-digit password using the digits 0 through 9? You may repeat numbers.
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<span>Each number had 10 possibilities. So to calculate the number of possibilities for two numbers multiply 10 by 10. This means that for all 4 digits the number of possible permutations is 10x10x10x10 or 10 to the power 4. This equals to 10,000 therefore D.

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7 0
3 years ago
The axis of symmetry for the graph of the function is f(x) = x2 + bx + 10 is x = 6. What is the value of b?
joja [24]

Answer:

b=-12

Step-by-step explanation:

we have

f(x)=x^{2}+bx+10

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex of the parabola

and the axis of symmetry is equal to x=h

In this problem we have the axis of symmetry x=6

so

the x-coordinate of the vertex is equal to 6  

therefore

For x=6+1=7 -----> one unit to the right of the vertex

Find the value of f(7)

f(7)=7^{2}+b(7)+10

f(7)=59+7b

For x=6-1=5 -----> one unit to the left of the vertex

Find the value of f(5)

f(5)=5^{2}+b(5)+10

f(5)=35+5b

Remember that

f(5)=f(7) ------> the x-coordinates are at the same distance from the axis of symmetry

so

59+7b=35+5b ------> solve for b

7b-5b=35-59

2b=-24

b=-12


3 0
2 years ago
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What's the full answer
Jet001 [13]
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