Answer: b
Step-by-step explanation:
For a parabola equation ax^2+bx+c, the vertex would be -b/2a
Therefore, the x coordinate of the minimum would be -(-32)/2(2)=32/4=8
That is the "h" part of the equation.
Now, we need to find the y coordinate, which will be the "k" part of the equation. We can find that by plugging in x=8 into the equation: 2(8)^2-32(8)+56= -72
Therefore, we plug (h,k) and a in, and get the equation y=2(x-8)^2-72
The x coordinate of the minimum is 8
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101.28-96 = 5.28
5.28/96 = 0.055
0.055 x 100% = 5.5%