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marin [14]
3 years ago
6

A company produces boxes of dvds of a rate at 52 boxes per hour. they begin to produce boxes when they first open for the day an

d after 3 hours they have 404 boxes in stock.
How many boxes are in stock when they open?

Write a linear model for the amount of boxes b ,of a function of the number of hours since they opened ,h.

What is the slope of the linear model you found above ?

What is the y-intercept of the linear function you found above?

Use your model to predict the number of boxes in stock at the end of an 8 hour shift
Mathematics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

this number 1 and 2  is the only one i could answer

Step-by-step explanation:

1.In three hours, at 52 boxes an hour, they produce 3(52) = 156 boxes.

If they then have 404 boxes on hand, they must have had

404 - 156 = 248 boxes when the store opened.

2.N=404-3 times 52

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The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,
Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

If the mean number of arrivals is 10

This means that \mu = 10

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is P(X \leq 10)

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045

P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045

P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023

P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076

P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189

P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378

P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631

P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901

P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126

P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251

P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831

58.31% probability that there are no more than 10 arrivals.

8 0
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the population of a small city grows by 600 every year. If there were 900 people initially, find the population of the city 60 y
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Answer:

36900

Step-by-step explanation:

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Sladkaya [172]
I will go about solving this using the elimination method.

First, convert the equations.

10x + y = -20
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6x = -8

Third, you want to solve the equation.

6x = -8 (divide by 6)
x = -1 \frac{1}{3}

Fourth, solve for y by inserting the answer for x into one of the equations.

10(-1 \frac{1}{3}) + y = -20
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The solution for this system of equations is (-1 \frac{1}{3}, -6 \frac{2}{3}).
7 0
3 years ago
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Ella swims four times a week at her clubs pool. She swims the same number of laps on Monday,Wednesday,Friday,and 15 laps on Satu
Reika [66]

She swims 12 laps on Monday.

Step-by-step explanation:

Total laps = 51 laps

Laps on Saturday = 15 laps

Let,

x be the number of laps on Monday, Wednesday and Friday each.

According to given statement;

Monday+Wednesday+Friday+Saturday = 51

x+x+x+15=51\\3x=51-15\\3x=36

Dividing both sides by 3

\frac{3x}{3}=\frac{36}{3}\\x=12

She swims 12 laps on Monday.

Keywords: addition, division

Learn more about division at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

7 0
3 years ago
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