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marin [14]
3 years ago
6

A company produces boxes of dvds of a rate at 52 boxes per hour. they begin to produce boxes when they first open for the day an

d after 3 hours they have 404 boxes in stock.
How many boxes are in stock when they open?

Write a linear model for the amount of boxes b ,of a function of the number of hours since they opened ,h.

What is the slope of the linear model you found above ?

What is the y-intercept of the linear function you found above?

Use your model to predict the number of boxes in stock at the end of an 8 hour shift
Mathematics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

this number 1 and 2  is the only one i could answer

Step-by-step explanation:

1.In three hours, at 52 boxes an hour, they produce 3(52) = 156 boxes.

If they then have 404 boxes on hand, they must have had

404 - 156 = 248 boxes when the store opened.

2.N=404-3 times 52

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4 0
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The circumference of a circle is 22 meters. What is the approximate
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2 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
Plesse help geomrety
marin [14]
X + number = 114
Make sure x is 50
Then switch it and
X + number = 50
Make sure it’s 14
8 0
2 years ago
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