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Iteru [2.4K]
3 years ago
14

A moving cyclist sees traffic up ahead and begins slowing down with constant acceleration. After slowing down for 0.5\,\text{s}0

.5s0, point, 5, start text, s, end text, the cyclist has travelled forward 2\,\text m2m2, start text, m, end text and has a speed of 10\,\dfrac{\text{km}}{\text{h}}10 h km ​ 10, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction. We want to find the acceleration of the cyclist while slowing down to 10\,\dfrac{\text{km}}{\text{h}}10 h km ​ 10, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction.
Physics
1 answer:
Helen [10]3 years ago
8 0

Answer:

Δx=vt−21​at2

Explanation:

We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.

In this problem, the target unknown is the acceleration as the cyclist slows down.

Assuming the initial direction of travel is the positive direction, our known variables are

t=0.5s

v=10km/h

Δx=2m

Since we don't know the initial velocity (Vo), and we are not asked to find (Vo)  we could use the kinematic formula that is missing (Vo) to solve for the target unknown, A

Δx=vt−21​at

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A 5 kg ball takes 13.3 seconds for one revolution around the circle. What's the magnitude of the angular velocity of this motion
Tcecarenko [31]

Answer: 0.47 rad/sec

Explanation:

By definition, the angular velocity is the rate of change of the angle traveled with time, so we can state the following:

ω = ∆θ/ ∆t

Now, we are told that in 13.3 sec, the ball completes one revolution around the circle, which means that, by definition of angle, it has rotated 2 π rad (an arc of 2πr over the radius r), so we can find ω as follows:

ω = 2 π / 13.3 rad/sec = 0.47 rad/sec

6 0
3 years ago
Read 2 more answers
Help pls i need this right now
pantera1 [17]

Answer:

The x-component of F_{3} is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O (1)

Where:

\vec F_{1}, \vec F_{2}, \vec F_{3} - External forces exerted on the ring, measured in newtons.

\vec O - Vector zero, measured in newtons.

If we know that \vec F_{1} = (70.711,70.711)\,[N], \vec F_{2} = (-126.859, 46.173)\,[N], F_{3} = (F_{3,x},F_{3,y}) and \vec O = (0,0)\,[N], then we construct the following system of linear equations:

\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N (2)

\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N (3)

The solution of this system is:

F_{3,x} = 56.148\,N, F_{3,y} = -116.884\,N

The x-component of F_{3} is 56.148 newtons.

5 0
2 years ago
In a car moving at constant acceleration, you travel 230 m between the instants at which the speedometer reads 40 km/h and 70 km
Goryan [66]
The relationship between the distance covered, initial and final speeds, and time can be expressed through the equation,

First equation,

                    2ad = Vf² - Vi²

Substituting the known values,
                   2(a)(0.230 km) = (70 km/h)² - (40 km/h)²
The value of a from the equation is 7173.92 km/h².

Second equation,
                   d = (Vi)(t) + 0.5at²

Substituting the known values,
                    0.230 km = (40 km/h)(t) + (0.5)(7173.92 km/h²)(t²)

The value of t from the equation is 4.1818 x 10^-3 hours which is also equal to 0.2509 minutes or 15 seconds.

Answer: 15 seconds
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julsineya [31]
I believe the correct answer is the second option. Planting of trees on sloped surfaces is a method of conservation that utilizes the roots of plants. Planting trees on such areas would prevent hazards and maintain the soil formation future since the roots would hold the soil together preventing or minimizing any soil erosion.
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3 years ago
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I need help asap plss this is important ​
Lady_Fox [76]
I think it would be “use reasoning statements to show how the data supports your claim”
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3 years ago
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