Answer: 0.075
explanation:
you can use one of the equations of motion.
2as =v^2 - u^2
we shall make acceleration the subject as that's what we need to find out
a = (v^2 - u^2) / (2 × s)
now substitute the given values:
final speed would be zero as the airplane stops.
a = (75 - 0) / ( 2 × 500)
a = 75 ÷ 1000
a = 0.075 meters per second squared.
Answer:
the initial velocity of bullet is u = 330.335 m /s
Explanation:
given,
mass of bullet(m) = 7 g
Mass of pendulum ( M ) = 1.5- kg
The bullet emerges from the block with a speed (V) = 200 m/s
The maximum height ( h ) = 12 cm.
Let the initial speed of the bullet be ' u '
Apply, Law of conservation of momentum :
m u = ( m + M ) V ...............................(1)
Apply, Law of conservation of Energy :
...............(2)
From equation (1) and equation (2) , we have
But V = √2gh
u = 330.335 m /s
hence, the initial velocity of bullet is u = 330.335 m /s
Answer:
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Biotic is the living factors while abiotic is nonliving such as a rock
Answer:
I think the answer is D,54 joules