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katovenus [111]
3 years ago
7

Which of the following methods of soil conservation uses the roots of plants as anchors in the soil? (2 points) Adding fertilize

rs to soil Planting trees on sloped surfaces Adding beneficial organisms to soil Watering grasses to add moisture
Physics
2 answers:
julsineya [31]3 years ago
8 0
I believe the correct answer is the second option. Planting of trees on sloped surfaces is a method of conservation that utilizes the roots of plants. Planting trees on such areas would prevent hazards and maintain the soil formation future since the roots would hold the soil together preventing or minimizing any soil erosion.
romanna [79]3 years ago
8 0
Planting trees on sloped surfaces.
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What is the impulse of a 3 kg object that starts from rest and moves to 20 m/s?
IrinaK [193]

Answer:

The impulse on the object is 60Ns.

Explanation:

Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.

F = m a

F = m(\frac{v_{2}  - v_{1} }{t})

⇒     Ft = m(v_{2} - v_{1})

where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, v_{1} is its initialvelocity and v_{2} is the final velocity of the object.

Therefore,

impulse = Ft = m(v_{2} - v_{1})

From the question, m = 3kg, v_{1} = 0m/s and v_{2} = 20m/s.

So that,

Impulse = 3 (20 - 0)

             = 3(20)

             = 60Ns

The impulse on the object is 60Ns.

8 0
3 years ago
The speed of the 2 kg cart after 5 seconds is ? cm/s.
motikmotik
The answer to this question is 1cm/s
3 0
3 years ago
A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to i
deff fn [24]
mgh =7*2*9.8=137.2. It should be the answer.
4 0
3 years ago
Read 2 more answers
( Can someone help? )
Murrr4er [49]

Answer:

Answer would be 0.33

Explanation:

Calculations

8 0
3 years ago
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A bell rings at a frequency of 75hz on a warm 25 degree evening. calculate the...
allochka39001 [22]

Answer:

Explanation:

We need 2 different equations for this problem: first the velocity of sound equation, then the frequency of the sound equation.

The velocity of sound is found in:

v = 331.5 + .606T

We need to find that first in order to fill it into the frequency equation which is

f=\frac{v}{\lambda} where v is the velocity we will find the part a, f is frequency and lambda is the wavelength. Starting with the velocity of the sound:

v = 331.5 + .606(25) and

v = 331.5 + 15 and rounding correctly using the rules for sig fig when adding:

v = 347 m/s

Filling that into the frequency equation:

75=\frac{347}{\lambda} and

\lambda=\frac{347}{75} so

\lambda=4.6m

7 0
3 years ago
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