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Ann [662]
3 years ago
14

-3x + y > 6 solve for y

Mathematics
1 answer:
Mumz [18]3 years ago
3 0

y > 6 + 3x
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Point A is at (-1,-9) and Point M is at (0.5,-2.5).
leva [86]
  • Midpoint Formula: (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})

So firstly, let's start with the x-coordinates. Since we know the midpoint's x-coordinate and point A's x-coordinate, we can solve for point B's x-coordinate as such:

\frac{-1+x}{2}=0.5\\\\-1+x=1\\\\x=2

Next, do the same thing except solve for the y-coordinate and using point A's y-coordinate and the midpoint's y-coordinate:

\frac{-9+y}{2}=-2.5\\\\-9+y=-5\\\\y=4

<u>Putting it together, point B's coordinates are (2,4).</u>

4 0
2 years ago
Mr.Davis drives 496 miles in eight hours. At this rate, how many miles does he drive in six hours?
Lynna [10]

Answer:

Step-by-step explanation:

496m=8h

Figure for 1 hour.

496/8=62

Now do

62x6=372m

Yes, you are correct.

3 0
2 years ago
Examine the system of equations. −5x + 5y = 40 4x + 3y = 24 What is the solution?
Solnce55 [7]
-5x + 5y = 40             -20x +20y =160               -5x + 5(8) = 40
4x + 3y = 24               20x +15y =120                -5x + 40 = 40
                                           35y = 280                   -5x =0
                                               y = 8                         x = 0

Hope you understood this
3 0
3 years ago
Read 2 more answers
The question is in the picture!​
djverab [1.8K]
46$ do the division. god bless
6 0
2 years ago
Image a coordinate plane with points plotted at ordered pairs Q(-4,4) R(2,4) S(5,-3) T(2,-3) and U (-4,-3) what is the area of t
pogonyaev

In counterclockwise order that's


R(2,4), Q(-4,4), U(-4,3), T(2,-3), S(5,-3)


That's a trapezoid, height 7 upper base 6, lower base 9, so average base 15/2 and area 7(15)/2 = 105/2 = 52.5.


Answer: 52.5


The shoelace theorem gives the answer without thinking. We write the list on top of itself shifted and add up the cross produces:


R(2,4), Q(-4,4), U(-4,-3), T(2,-3), S(5,-3)

Q(-4,4), U(-4,-3), T(2,-3), S(5,-3), R(2,4),


A = \frac 1 2 | 2(4)-(4)(-4) + -4(-3)-(-4)(4) + -4(-3)- -3(2) + 2(-3)-(-3)(5) + 5(4)- -3(2)| = \frac{105}{2} \quad\checkmark




8 0
3 years ago
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