What digit(s) can be in the one's place of a number that has 5 as a factor?

2 answers:

max2010maxim [7]3 years ago

6 0

Any number that ends with a 0 or a 5 would be a multiple of 5 because as you multipy numbers by 5 you start to see a pattern in the ones place of 5,0,5,0,5,0,5,0,... And so on forever

ololo11 [35]3 years ago

3 0

0 and 5 can be in the one's place of a number that has 5 as a factor.

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1. Find the vertex of the following: y = (x - 4)(x - 10) *

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1. (7,-9)

2. (4,0) and (10,0)

3. (3,0) and (-3,0)

4. (0,-9)

5. (-1,-32)

Step-by-step explanation:

To find the vertex use the formula

$\frac{-b}{2a}$

First make the equation into a quadratic equation.

$(x-4)(x-10)\\x^{2} -10x-4x+40\\x^{2} -14x+40$

Now it is in the form

$ax^{2} +bx+c=0$

Now we can substitute the values

$\frac{-(-14)}{2(1)} \\\frac{14}{2} \\7$

Now we have 7 as our x value for the vertex we can substitute for y,

$x^{2} -14x+40=y\\(7)^{2} -14(7)+40=y\\49-98+4=y\\y=-9$

So the vertex for 1 is (7,-9)

To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.

$x-4=0\\x=4\\\\x-10=0\\x=10$