What digit(s) can be in the one's place of a number that has 5 as a factor?

2 answers:

max2010maxim [7]3 years ago

6 0

Any number that ends with a 0 or a 5 would be a multiple of 5 because as you multipy numbers by 5 you start to see a pattern in the ones place of 5,0,5,0,5,0,5,0,... And so on forever

ololo11 [35]3 years ago

3 0

0 and 5 can be in the one's place of a number that has 5 as a factor.

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<u>Factoring:</u>

This equation cannot be factored because its roots are irrational (as shown by solving with the quadratic formula). Also, to factor a quadratic equation, you need to find a pair of numbers whose product is equal to the c term (-5) and whose sum is equal to the b term (-6). There is no pair of numbers which satisfies this, further showing that the equation cannot be factored.

<u>Quadratic Formula:</u>

The quadratic formula is x= $\frac{-b ± \sqrt{b^{2}-4ac } }{2a}$ .

First, you need to find the a, b and c terms of your equation. They are 1, -6, and -5 respectively.

Now, you must plug in to the equation and solve for x. You must do so twice, once with a plus sign in the numerator and once with a minus.

$\frac{6 ± \sqrt{(-6)^{2}-4(1)(-5) } }{2(1)} \\\frac{6 ± \sqrt{36+20} }{2} \\\frac{6 ± \sqrt{56} }{2} \\\ \frac{6 ± 2\sqrt{14} }{2} \\3+\sqrt{14} \\3-\sqrt{14}$

The answers are 3+√14 and 3-√14.

Hope this helps!!

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