f(x) being even means
f(x) = f(-x)
So the zeros come in positive and negative pairs. If there are an odd number of intercepts like there are here, it's because one of them is x=0 which is its own negation.
Given zero x=6 we know x=-6 is also a zero.
So we know three zeros, and know the other two zeros are a positive and negative pair.
The only choice with (-6,0) and (0,0) is A.
Choice A
Answer:
<em>f(x) = x² (2+i)x-15-3i</em>
Step-by-step explanation:
Since the zeros of the equation are -3 and 5+i, hence the factors of the polynomial in x is (x+3) and (x-(5+i))
Multiplying both factors
f(x) = (x+3)(x-(5+i))
f(x) = (x²-(5+i)x+3x -3(5+i))
f(x) = x² - (5+i- 3)x -15-3i
f(x) = x² (2+i)x-15-3i
<em>hence the required polynomial function in x is f(x) = x² (2+i)x-15-3i</em>
Answer: C. f(x)=x^2+16x+63
Step-by-step explanation:
Vertex=(8,-1)
Focus=(8,-3/4)
Axis of Symmertry= x=8
Directrix= y=-5/4
I hope this helps you!
Answer:
1.01789228E-5
Step-by-step explanation:
hope this helped :)
