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4 years ago

Hey Katie ;) get it chemistry

Chemistry

2 answers:

Harrizon [31]4 years ago

4 0

Answer:

um ogey kAtIe

Explanation:

stich3 [128]4 years ago

3 0

Answer:

Omg thx you bestie

Explanation:

Purr betsue that's all

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Calculate the value of E°cell for the following reaction:2Au(s) + 3Ca2+(aq) → 2Au3+(aq) + 3Ca(s)Au3+(aq) + 3e- → Au(s) E° = 1.50

uranmaximum [27]

Answer: The standard electrode potential of the cell is -4.37 V

Explanation:

For the given cell reaction:

$2Au(s)+3Ca^{2+}(aq.)\rightarrow 2Au^{3+}(aq.)+3Ca(s)$

The half reactions follows:

Oxidation half reaction: $Au(s)\rightarrow Au^{3+}(aq.)+3e^-;E^o_{Au^{3+}/Au}=1.50V$ ( × 2 )

Reduction half reaction: $Ca^{2+}(aq.)+2e^-\rightarrow Ca(s);E^o_{Ca^{2+}/Ca}=-2.87V$ ( × 3 )

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-2.87-(1.50)=-4.37V$

Hence, the standard electrode potential of the cell is -4.37 V

8 0

3 years ago

dezoksy [38]

Answer:

I don't know

Explanation:

sorry i just need point to ask so i have comment

5 0

3 years ago

lord [1]

Answer:

$\boxed{6.08 \times 10^{23}}$

Explanation:

Data:

I = 2.15 A

t = 8 min 24 s

T = 26.0 °C

V = 65.4 mL

p = 774.2 To

1. Write the equation for the half-reaction

2H₂O ⟶ O₂ + 4H⁺ + 4e⁻

2. Calculate the moles of oxygen

$p = \text{774.2 To} \times \dfrac{\text{1 atm}}{\text{760 To}} = \text{1.0187 atm}$

V = 0.0654 L

T = (26.0 + 273.15) K = 299.15 K

$\begin{array}{rcl}pV& = & nRT\\1.0189 \times 0.0654 & = & n \times 0.08206 \times 299.15\\0.06662 & = & 24.55n\\\\n & = & \dfrac{0.06662}{24.55}\\\\n & = & 2.714 \times 10^{-3}\\\end{array}$

3. Calculate the moles of electrons

$\text{n} = \text{2.714 $\times 10^{-3}$ mol oxygen} \times \dfrac{\text{4 mol electrons}}{\text{ 1 mol ozygen}} = \text{ 0.01086 mol electrons}$

4. Calculate the number of coulombs

t = 8 min 24 s =504 s

Q = It = 504 s × 2.10 C·s⁻¹= 1058 C

5. Calculate the number of electrons

$\text{No. of electrons} = \text{1058 C} \times \dfrac{\text{1 electron}}{1.602 \times 10^{-19}\text{ C}} = 6.607 \times 10^{21}\text{ electrons}$

6. Calculate Avogadro's number

$N_{\text{A}} = \dfrac{6.607 \times 10^{21}}{0.01086} = \mathbf{6.08 \times 10^{23}}\\\\\text{The experimental value of Avogadro's number is } \boxed{\mathbf{6.08 \times 10^{23}}}$

3 0

4 years ago

Cl2 + H2 + 2HCI

Cloud [144]

Answer:

1 and 2

Explanation:

The given equation is:

Cl₂ + H₂ → 2HCl

A coefficient is the variable or number before a chemical specie.

In this reaction Cl₂ and H₂ are the reactants;

The coefficient of Cl₂ is 1,

H₂ is 1,

HCl is 2

The subscript is the number to the lower power after a chemical specie is denoted.

For Cl₂, it is 2

6 0

3 years ago

PLZ HELP THIS IS DUE TODAY!!!!!!

Goshia [24]

It would be letter C, because the molecules of solids can have a little vibration in their places.
The first one is for gas, so it's wrong. The second one is for liquids. And finally, the third one is right.

5 0

3 years ago