Answer:
Hydrogen: 5
Carbon:3
Nitrogen:3
Oxygen: 9
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Below are the choices:
a)0.2168 atm
<span>b)4.613 atm </span>
<span>c)34.60 atm </span>
<span>d467.4 atm
</span>
1 atm = 760mmHg : Therefore:
<span>3,506mmHg = 3,506/760 = 4.613 atm
</span>B is correct answer.
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<u>Answer:</u> In heterogeneous mixture, the composition remains variable throughout.
<u>Explanation:</u>
For the given options:
Homogeneous mixtures are defined as the mixtures that appears uniformly throughout the solution and the particle size or shapes are not different. The composition remains constant throughout.
A solution is defined as the solution in which the components gets completely dissolved in it. Particles are evenly spread in these solutions. These solution does not scatter light falling on it. The composition remains constant throughout.
An amorphous solid is defined as the solid in which the constituent particles of the matter are arranged in the random manner. The composition remains constant throughout.
A heterogeneous mixture is defined as the mixture in which component are unevenly spread throughout the solution. The size and shape of the particles differ in these mixtures. These mixture scatter the light falling on it. The composition do not remains constant throughout.
Compound is defined as the chemical specie which is formed by the combination of two or more different type of atoms. <u>For Example:</u>
etc...The composition remains constant throughout.
Hence, in heterogeneous mixture, the composition remains variable throughout.
Answer:
Percentage of first isotope = 69.152 %
Percentage of second isotope = 30.848 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope:
Let % = x %
Mass = 62.9296 amu
For second isotope:
% = 100 - x % (Since, there are only two isotopes)
Mass = 64.9278 amu
Average mass = 63.546 amu
Thus,
Solving,
1.9982 x = 138.18
Thus,
<u>Percentage of first isotope = x = 69.152 %</u>
<u>Percentage of second isotope = 100 - x % = 30.848 %</u>
Answer:
The answer to your question is below
Explanation:
Propane = C₃H₈
Process
1.- Write the chemical reaction
C₃H₈ + O₂ ⇒ CO₂ + H₂O
balanced chemical reaction
C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂O
Reactants Elements Products
3 C 3
8 H 8
10 O 10
b) Standard enthalpy
Propane -104.7 kJ/mol
Oxygen 0 kJ/mol
Carbon dioxide -393.5 kJ/mol
Water -241.8 kJ/mol
ΔH° = ∑ΔH° products - ∑H° reactants
ΔH° = 3(-393.5) + 4(-241.8) - [(-104.7) + 0]
-Simplification
ΔH° = -1180.5 kJ/mol - 967.2 kJ/mol + 104.7 kJ/mol
ΔH° = - 2042.5 kJ/mol
This reaction is exothermic because ΔH° is negative.