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3 years ago

Which example is most likely powered by direct current?

Physics

1 answer:

dem82 [27]3 years ago

5 0

In all household connections the supply is always AC current

B) a household electric frying pan

C) The lamp in a kitchen ceiling

D) The bathroom ceiling fan

Above all three are working on AC current as per supply to household

So here for DC current the correct answer must be

<em>A. the glove-compartment light in an automobile</em>

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What is this ???????????

babymother [125]

A, something to remember is that if the numbers are even the answer too will be even. Every time hope this helps :>

8 0

3 years ago

Read 2 more answers

3. A car travelling at 20. m/s stops in a distance of 40. m. What is its

KIM [24]

Answer:

It was a joke i was getting the answer

Explanation:

Be percent karen

4 0

3 years ago

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does

alina1380 [7]

a)]An expression for the magnitude of charge transferred Q is Q = W/V.

b) The magnitude of the charge, in coulombs is 1.02 x 10⁻⁹ Coulomb.

c) Number of electrons in this are 63.75 x 10⁸ electrons.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does W= 1x10⁻⁶ J of work transferring the charge.

a) Work done = Charge x potential

W = Q x V

Q = W/V

b)Substitute the values into the expression, we have

|Q| = 1x10⁻⁶/9800

|Q| = 1.02 x 10⁻⁹ Coulomb

c) No of electrons = total charge /charge on electron

n = 1.02 x 10⁻⁹/1.6 x 10⁻¹⁹

n = 63.75 x 10⁸ electrons

Learn more about electrons.

brainly.com/question/1255220

#SPJ1

6 0

2 years ago

A horizontal 649 N merry-go-round of radius 1.05 m is started from rest by a constant horizontal force of 61.3 N applied tangent

nexus9112 [7]

Answer:

The kinetic energy of the merry-go-round is 632.82 J

Explanation:

Given;

weight of the merry-go-round, W = 649 N

radius of the merry-go-round, r = 1.05 m

applied horizontal force, F = 61.3 N

acceleration due to gravity, g = 9.8 m/s²

mass of merry-go-round, m = W/g

= 649/9.8 = 66.225 kg

moment of inertia of merry-go-round, I = ¹/₂mr²

= ¹/₂ x 66.225 x (1.05)²

= 36.507 kg.m²

Angular acceleration of the merry-go-round, α

τ = Iα = Fr

α = Fr / I

Where;

α is angular acceleration

α = (61.3 x 1.05) / 36.507

α = 1.763 rad/s²

Angular velocity of the merry-go-round, ω

ω = αt

ω = 1.763 x 3.34

ω = 5.888 rad/s

Finally, the kinetic energy of the merry-go-round, K.E

K.E = ¹/₂Iω²

K.E = ¹/₂ x 36.507 x (5.888)²

K.E = 632.82 J

4 0

3 years ago

someone help me please haha Calculate the braking force of a lorry decelerating at a rate of 8 m/s² with a mass of 5000 kg.

ICE Princess25 [194]

Answer:

40000 N

Explanation:

Force: This cam be defined as the product of mass and acceleration.

From the question,

The braking force of the lorry will be the same in magnitude as the force at which the lorry is moving.

F = ma..................... Equation 1

Where m = mass of the lorry, a = acceleration/deceleration of the lorry.

Given: m = 5000 kg, a = 8 m/s²

Substitute these values into equation 1

F = 5000(8)

F = 40000 N

6 0

3 years ago